Question:
Find the average of even numbers from 8 to 1410
Correct Answer
709
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 8 to 1410
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 8 to 1410 are
8, 10, 12, . . . . 1410
After observing the above list of the even numbers from 8 to 1410 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 8 to 1410 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 8 to 1410
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 1410
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 8 to 1410
= 8 + 1410/2
= 1418/2 = 709
Thus, the average of the even numbers from 8 to 1410 = 709 Answer
Method (2) to find the average of the even numbers from 8 to 1410
Finding the average of given continuous even numbers after finding their sum
The even numbers from 8 to 1410 are
8, 10, 12, . . . . 1410
The even numbers from 8 to 1410 form an Arithmetic Series in which
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 1410
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 8 to 1410
1410 = 8 + (n – 1) × 2
⇒ 1410 = 8 + 2 n – 2
⇒ 1410 = 8 – 2 + 2 n
⇒ 1410 = 6 + 2 n
After transposing 6 to LHS
⇒ 1410 – 6 = 2 n
⇒ 1404 = 2 n
After rearranging the above expression
⇒ 2 n = 1404
After transposing 2 to RHS
⇒ n = 1404/2
⇒ n = 702
Thus, the number of terms of even numbers from 8 to 1410 = 702
This means 1410 is the 702th term.
Finding the sum of the given even numbers from 8 to 1410
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 8 to 1410
= 702/2 (8 + 1410)
= 702/2 × 1418
= 702 × 1418/2
= 995436/2 = 497718
Thus, the sum of all terms of the given even numbers from 8 to 1410 = 497718
And, the total number of terms = 702
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 8 to 1410
= 497718/702 = 709
Thus, the average of the given even numbers from 8 to 1410 = 709 Answer
Similar Questions
(1) Find the average of the first 3646 even numbers.
(2) Find the average of odd numbers from 9 to 1317
(3) Find the average of the first 3916 odd numbers.
(4) Find the average of odd numbers from 11 to 857
(5) Find the average of odd numbers from 3 to 383
(6) Find the average of the first 1777 odd numbers.
(7) Find the average of the first 678 odd numbers.
(8) What is the average of the first 1620 even numbers?
(9) What will be the average of the first 4329 odd numbers?
(10) What will be the average of the first 4464 odd numbers?