Question:
Find the average of even numbers from 8 to 1432
Correct Answer
720
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 8 to 1432
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 8 to 1432 are
8, 10, 12, . . . . 1432
After observing the above list of the even numbers from 8 to 1432 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 8 to 1432 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 8 to 1432
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 1432
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 8 to 1432
= 8 + 1432/2
= 1440/2 = 720
Thus, the average of the even numbers from 8 to 1432 = 720 Answer
Method (2) to find the average of the even numbers from 8 to 1432
Finding the average of given continuous even numbers after finding their sum
The even numbers from 8 to 1432 are
8, 10, 12, . . . . 1432
The even numbers from 8 to 1432 form an Arithmetic Series in which
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 1432
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 8 to 1432
1432 = 8 + (n – 1) × 2
⇒ 1432 = 8 + 2 n – 2
⇒ 1432 = 8 – 2 + 2 n
⇒ 1432 = 6 + 2 n
After transposing 6 to LHS
⇒ 1432 – 6 = 2 n
⇒ 1426 = 2 n
After rearranging the above expression
⇒ 2 n = 1426
After transposing 2 to RHS
⇒ n = 1426/2
⇒ n = 713
Thus, the number of terms of even numbers from 8 to 1432 = 713
This means 1432 is the 713th term.
Finding the sum of the given even numbers from 8 to 1432
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 8 to 1432
= 713/2 (8 + 1432)
= 713/2 × 1440
= 713 × 1440/2
= 1026720/2 = 513360
Thus, the sum of all terms of the given even numbers from 8 to 1432 = 513360
And, the total number of terms = 713
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 8 to 1432
= 513360/713 = 720
Thus, the average of the given even numbers from 8 to 1432 = 720 Answer
Similar Questions
(1) Find the average of the first 4229 even numbers.
(2) What is the average of the first 550 even numbers?
(3) Find the average of the first 2593 even numbers.
(4) Find the average of the first 4504 even numbers.
(5) Find the average of the first 4576 even numbers.
(6) Find the average of the first 2556 even numbers.
(7) Find the average of odd numbers from 15 to 387
(8) Find the average of the first 1945 odd numbers.
(9) Find the average of even numbers from 8 to 1130
(10) What will be the average of the first 4618 odd numbers?