Question:
Find the average of even numbers from 8 to 1448
Correct Answer
728
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 8 to 1448
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 8 to 1448 are
8, 10, 12, . . . . 1448
After observing the above list of the even numbers from 8 to 1448 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 8 to 1448 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 8 to 1448
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 1448
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 8 to 1448
= 8 + 1448/2
= 1456/2 = 728
Thus, the average of the even numbers from 8 to 1448 = 728 Answer
Method (2) to find the average of the even numbers from 8 to 1448
Finding the average of given continuous even numbers after finding their sum
The even numbers from 8 to 1448 are
8, 10, 12, . . . . 1448
The even numbers from 8 to 1448 form an Arithmetic Series in which
The First Term (a) = 8
The Common Difference (d) = 2
And the last term (ℓ) = 1448
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 8 to 1448
1448 = 8 + (n – 1) × 2
⇒ 1448 = 8 + 2 n – 2
⇒ 1448 = 8 – 2 + 2 n
⇒ 1448 = 6 + 2 n
After transposing 6 to LHS
⇒ 1448 – 6 = 2 n
⇒ 1442 = 2 n
After rearranging the above expression
⇒ 2 n = 1442
After transposing 2 to RHS
⇒ n = 1442/2
⇒ n = 721
Thus, the number of terms of even numbers from 8 to 1448 = 721
This means 1448 is the 721th term.
Finding the sum of the given even numbers from 8 to 1448
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 8 to 1448
= 721/2 (8 + 1448)
= 721/2 × 1456
= 721 × 1456/2
= 1049776/2 = 524888
Thus, the sum of all terms of the given even numbers from 8 to 1448 = 524888
And, the total number of terms = 721
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 8 to 1448
= 524888/721 = 728
Thus, the average of the given even numbers from 8 to 1448 = 728 Answer
Similar Questions
(1) Find the average of even numbers from 10 to 1268
(2) Find the average of the first 1959 odd numbers.
(3) Find the average of odd numbers from 13 to 425
(4) Find the average of even numbers from 12 to 678
(5) What will be the average of the first 4538 odd numbers?
(6) Find the average of odd numbers from 3 to 539
(7) Find the average of even numbers from 12 to 514
(8) Find the average of even numbers from 10 to 1708
(9) Find the average of even numbers from 10 to 704
(10) What is the average of the first 1104 even numbers?