Average
MCQs Math


Question:     Find the average of even numbers from 10 to 112


Correct Answer  61

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 112

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 112 are

10, 12, 14, . . . . 112

After observing the above list of the even numbers from 10 to 112 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 112 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 112

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 112

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 112

= 10 + 112/2

= 122/2 = 61

Thus, the average of the even numbers from 10 to 112 = 61 Answer

Method (2) to find the average of the even numbers from 10 to 112

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 112 are

10, 12, 14, . . . . 112

The even numbers from 10 to 112 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 112

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 112

112 = 10 + (n – 1) × 2

⇒ 112 = 10 + 2 n – 2

⇒ 112 = 10 – 2 + 2 n

⇒ 112 = 8 + 2 n

After transposing 8 to LHS

⇒ 112 – 8 = 2 n

⇒ 104 = 2 n

After rearranging the above expression

⇒ 2 n = 104

After transposing 2 to RHS

⇒ n = 104/2

⇒ n = 52

Thus, the number of terms of even numbers from 10 to 112 = 52

This means 112 is the 52th term.

Finding the sum of the given even numbers from 10 to 112

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 112

= 52/2 (10 + 112)

= 52/2 × 122

= 52 × 122/2

= 6344/2 = 3172

Thus, the sum of all terms of the given even numbers from 10 to 112 = 3172

And, the total number of terms = 52

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 112

= 3172/52 = 61

Thus, the average of the given even numbers from 10 to 112 = 61 Answer


Similar Questions

(1) Find the average of the first 720 odd numbers.

(2) Find the average of even numbers from 4 to 1138

(3) Find the average of the first 1930 odd numbers.

(4) Find the average of the first 1255 odd numbers.

(5) Find the average of the first 3426 odd numbers.

(6) Find the average of the first 1881 odd numbers.

(7) Find the average of even numbers from 12 to 1352

(8) Find the average of the first 2511 odd numbers.

(9) Find the average of the first 3231 even numbers.

(10) Find the average of the first 1154 odd numbers.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©