Question:
Find the average of even numbers from 10 to 114
Correct Answer
62
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 10 to 114
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 10 to 114 are
10, 12, 14, . . . . 114
After observing the above list of the even numbers from 10 to 114 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 114 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 10 to 114
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 114
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 10 to 114
= 10 + 114/2
= 124/2 = 62
Thus, the average of the even numbers from 10 to 114 = 62 Answer
Method (2) to find the average of the even numbers from 10 to 114
Finding the average of given continuous even numbers after finding their sum
The even numbers from 10 to 114 are
10, 12, 14, . . . . 114
The even numbers from 10 to 114 form an Arithmetic Series in which
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 114
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 10 to 114
114 = 10 + (n – 1) × 2
⇒ 114 = 10 + 2 n – 2
⇒ 114 = 10 – 2 + 2 n
⇒ 114 = 8 + 2 n
After transposing 8 to LHS
⇒ 114 – 8 = 2 n
⇒ 106 = 2 n
After rearranging the above expression
⇒ 2 n = 106
After transposing 2 to RHS
⇒ n = 106/2
⇒ n = 53
Thus, the number of terms of even numbers from 10 to 114 = 53
This means 114 is the 53th term.
Finding the sum of the given even numbers from 10 to 114
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 10 to 114
= 53/2 (10 + 114)
= 53/2 × 124
= 53 × 124/2
= 6572/2 = 3286
Thus, the sum of all terms of the given even numbers from 10 to 114 = 3286
And, the total number of terms = 53
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 10 to 114
= 3286/53 = 62
Thus, the average of the given even numbers from 10 to 114 = 62 Answer
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