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MCQs Math


Question:     Find the average of even numbers from 10 to 240


Correct Answer  125

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 240

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 240 are

10, 12, 14, . . . . 240

After observing the above list of the even numbers from 10 to 240 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 240 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 240

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 240

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 240

= 10 + 240/2

= 250/2 = 125

Thus, the average of the even numbers from 10 to 240 = 125 Answer

Method (2) to find the average of the even numbers from 10 to 240

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 240 are

10, 12, 14, . . . . 240

The even numbers from 10 to 240 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 240

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 240

240 = 10 + (n – 1) × 2

⇒ 240 = 10 + 2 n – 2

⇒ 240 = 10 – 2 + 2 n

⇒ 240 = 8 + 2 n

After transposing 8 to LHS

⇒ 240 – 8 = 2 n

⇒ 232 = 2 n

After rearranging the above expression

⇒ 2 n = 232

After transposing 2 to RHS

⇒ n = 232/2

⇒ n = 116

Thus, the number of terms of even numbers from 10 to 240 = 116

This means 240 is the 116th term.

Finding the sum of the given even numbers from 10 to 240

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 240

= 116/2 (10 + 240)

= 116/2 × 250

= 116 × 250/2

= 29000/2 = 14500

Thus, the sum of all terms of the given even numbers from 10 to 240 = 14500

And, the total number of terms = 116

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 240

= 14500/116 = 125

Thus, the average of the given even numbers from 10 to 240 = 125 Answer


Similar Questions

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(2) Find the average of the first 1940 odd numbers.

(3) Find the average of even numbers from 4 to 1050

(4) What will be the average of the first 4793 odd numbers?

(5) Find the average of the first 2605 odd numbers.

(6) Find the average of the first 4502 even numbers.

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