Question:
Find the average of even numbers from 10 to 328
Correct Answer
169
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 10 to 328
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 10 to 328 are
10, 12, 14, . . . . 328
After observing the above list of the even numbers from 10 to 328 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 328 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 10 to 328
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 328
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 10 to 328
= 10 + 328/2
= 338/2 = 169
Thus, the average of the even numbers from 10 to 328 = 169 Answer
Method (2) to find the average of the even numbers from 10 to 328
Finding the average of given continuous even numbers after finding their sum
The even numbers from 10 to 328 are
10, 12, 14, . . . . 328
The even numbers from 10 to 328 form an Arithmetic Series in which
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 328
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 10 to 328
328 = 10 + (n – 1) × 2
⇒ 328 = 10 + 2 n – 2
⇒ 328 = 10 – 2 + 2 n
⇒ 328 = 8 + 2 n
After transposing 8 to LHS
⇒ 328 – 8 = 2 n
⇒ 320 = 2 n
After rearranging the above expression
⇒ 2 n = 320
After transposing 2 to RHS
⇒ n = 320/2
⇒ n = 160
Thus, the number of terms of even numbers from 10 to 328 = 160
This means 328 is the 160th term.
Finding the sum of the given even numbers from 10 to 328
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 10 to 328
= 160/2 (10 + 328)
= 160/2 × 338
= 160 × 338/2
= 54080/2 = 27040
Thus, the sum of all terms of the given even numbers from 10 to 328 = 27040
And, the total number of terms = 160
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 10 to 328
= 27040/160 = 169
Thus, the average of the given even numbers from 10 to 328 = 169 Answer
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