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MCQs Math


Question:     Find the average of even numbers from 10 to 444


Correct Answer  227

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 444

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 444 are

10, 12, 14, . . . . 444

After observing the above list of the even numbers from 10 to 444 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 444 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 444

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 444

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 444

= 10 + 444/2

= 454/2 = 227

Thus, the average of the even numbers from 10 to 444 = 227 Answer

Method (2) to find the average of the even numbers from 10 to 444

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 444 are

10, 12, 14, . . . . 444

The even numbers from 10 to 444 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 444

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 444

444 = 10 + (n – 1) × 2

⇒ 444 = 10 + 2 n – 2

⇒ 444 = 10 – 2 + 2 n

⇒ 444 = 8 + 2 n

After transposing 8 to LHS

⇒ 444 – 8 = 2 n

⇒ 436 = 2 n

After rearranging the above expression

⇒ 2 n = 436

After transposing 2 to RHS

⇒ n = 436/2

⇒ n = 218

Thus, the number of terms of even numbers from 10 to 444 = 218

This means 444 is the 218th term.

Finding the sum of the given even numbers from 10 to 444

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 444

= 218/2 (10 + 444)

= 218/2 × 454

= 218 × 454/2

= 98972/2 = 49486

Thus, the sum of all terms of the given even numbers from 10 to 444 = 49486

And, the total number of terms = 218

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 444

= 49486/218 = 227

Thus, the average of the given even numbers from 10 to 444 = 227 Answer


Similar Questions

(1) Find the average of the first 2823 odd numbers.

(2) Find the average of the first 4239 even numbers.

(3) Find the average of the first 2650 odd numbers.

(4) Find the average of even numbers from 6 to 314

(5) What is the average of the first 756 even numbers?

(6) Find the average of the first 4494 even numbers.

(7) Find the average of odd numbers from 5 to 1091

(8) Find the average of even numbers from 6 to 1538

(9) Find the average of the first 1606 odd numbers.

(10) Find the average of odd numbers from 5 to 535


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