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MCQs Math


Question:     Find the average of even numbers from 10 to 470


Correct Answer  240

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 470

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 470 are

10, 12, 14, . . . . 470

After observing the above list of the even numbers from 10 to 470 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 470 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 470

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 470

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 470

= 10 + 470/2

= 480/2 = 240

Thus, the average of the even numbers from 10 to 470 = 240 Answer

Method (2) to find the average of the even numbers from 10 to 470

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 470 are

10, 12, 14, . . . . 470

The even numbers from 10 to 470 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 470

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 470

470 = 10 + (n – 1) × 2

⇒ 470 = 10 + 2 n – 2

⇒ 470 = 10 – 2 + 2 n

⇒ 470 = 8 + 2 n

After transposing 8 to LHS

⇒ 470 – 8 = 2 n

⇒ 462 = 2 n

After rearranging the above expression

⇒ 2 n = 462

After transposing 2 to RHS

⇒ n = 462/2

⇒ n = 231

Thus, the number of terms of even numbers from 10 to 470 = 231

This means 470 is the 231th term.

Finding the sum of the given even numbers from 10 to 470

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 470

= 231/2 (10 + 470)

= 231/2 × 480

= 231 × 480/2

= 110880/2 = 55440

Thus, the sum of all terms of the given even numbers from 10 to 470 = 55440

And, the total number of terms = 231

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 470

= 55440/231 = 240

Thus, the average of the given even numbers from 10 to 470 = 240 Answer


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