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MCQs Math


Question:     Find the average of even numbers from 10 to 480


Correct Answer  245

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 480

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 480 are

10, 12, 14, . . . . 480

After observing the above list of the even numbers from 10 to 480 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 480 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 480

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 480

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 480

= 10 + 480/2

= 490/2 = 245

Thus, the average of the even numbers from 10 to 480 = 245 Answer

Method (2) to find the average of the even numbers from 10 to 480

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 480 are

10, 12, 14, . . . . 480

The even numbers from 10 to 480 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 480

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 480

480 = 10 + (n – 1) × 2

⇒ 480 = 10 + 2 n – 2

⇒ 480 = 10 – 2 + 2 n

⇒ 480 = 8 + 2 n

After transposing 8 to LHS

⇒ 480 – 8 = 2 n

⇒ 472 = 2 n

After rearranging the above expression

⇒ 2 n = 472

After transposing 2 to RHS

⇒ n = 472/2

⇒ n = 236

Thus, the number of terms of even numbers from 10 to 480 = 236

This means 480 is the 236th term.

Finding the sum of the given even numbers from 10 to 480

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 480

= 236/2 (10 + 480)

= 236/2 × 490

= 236 × 490/2

= 115640/2 = 57820

Thus, the sum of all terms of the given even numbers from 10 to 480 = 57820

And, the total number of terms = 236

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 480

= 57820/236 = 245

Thus, the average of the given even numbers from 10 to 480 = 245 Answer


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