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Question:     Find the average of even numbers from 10 to 770


Correct Answer  390

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 770

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 770 are

10, 12, 14, . . . . 770

After observing the above list of the even numbers from 10 to 770 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 770 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 770

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 770

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 770

= 10 + 770/2

= 780/2 = 390

Thus, the average of the even numbers from 10 to 770 = 390 Answer

Method (2) to find the average of the even numbers from 10 to 770

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 770 are

10, 12, 14, . . . . 770

The even numbers from 10 to 770 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 770

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 770

770 = 10 + (n – 1) × 2

⇒ 770 = 10 + 2 n – 2

⇒ 770 = 10 – 2 + 2 n

⇒ 770 = 8 + 2 n

After transposing 8 to LHS

⇒ 770 – 8 = 2 n

⇒ 762 = 2 n

After rearranging the above expression

⇒ 2 n = 762

After transposing 2 to RHS

⇒ n = 762/2

⇒ n = 381

Thus, the number of terms of even numbers from 10 to 770 = 381

This means 770 is the 381th term.

Finding the sum of the given even numbers from 10 to 770

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 770

= 381/2 (10 + 770)

= 381/2 × 780

= 381 × 780/2

= 297180/2 = 148590

Thus, the sum of all terms of the given even numbers from 10 to 770 = 148590

And, the total number of terms = 381

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 770

= 148590/381 = 390

Thus, the average of the given even numbers from 10 to 770 = 390 Answer


Similar Questions

(1) Find the average of even numbers from 12 to 442

(2) Find the average of odd numbers from 9 to 1237

(3) Find the average of odd numbers from 13 to 1045

(4) Find the average of even numbers from 10 to 266

(5) Find the average of odd numbers from 7 to 499

(6) Find the average of odd numbers from 13 to 335

(7) Find the average of the first 229 odd numbers.

(8) Find the average of odd numbers from 5 to 1057

(9) Find the average of even numbers from 12 to 330

(10) What will be the average of the first 4226 odd numbers?


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