Question:
Find the average of even numbers from 10 to 818
Correct Answer
414
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 10 to 818
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 10 to 818 are
10, 12, 14, . . . . 818
After observing the above list of the even numbers from 10 to 818 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 818 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 10 to 818
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 818
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 10 to 818
= 10 + 818/2
= 828/2 = 414
Thus, the average of the even numbers from 10 to 818 = 414 Answer
Method (2) to find the average of the even numbers from 10 to 818
Finding the average of given continuous even numbers after finding their sum
The even numbers from 10 to 818 are
10, 12, 14, . . . . 818
The even numbers from 10 to 818 form an Arithmetic Series in which
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 818
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 10 to 818
818 = 10 + (n – 1) × 2
⇒ 818 = 10 + 2 n – 2
⇒ 818 = 10 – 2 + 2 n
⇒ 818 = 8 + 2 n
After transposing 8 to LHS
⇒ 818 – 8 = 2 n
⇒ 810 = 2 n
After rearranging the above expression
⇒ 2 n = 810
After transposing 2 to RHS
⇒ n = 810/2
⇒ n = 405
Thus, the number of terms of even numbers from 10 to 818 = 405
This means 818 is the 405th term.
Finding the sum of the given even numbers from 10 to 818
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 10 to 818
= 405/2 (10 + 818)
= 405/2 × 828
= 405 × 828/2
= 335340/2 = 167670
Thus, the sum of all terms of the given even numbers from 10 to 818 = 167670
And, the total number of terms = 405
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 10 to 818
= 167670/405 = 414
Thus, the average of the given even numbers from 10 to 818 = 414 Answer
Similar Questions
(1) Find the average of even numbers from 10 to 546
(2) Find the average of the first 744 odd numbers.
(3) Find the average of odd numbers from 3 to 1373
(4) Find the average of the first 3923 even numbers.
(5) Find the average of the first 1787 odd numbers.
(6) Find the average of odd numbers from 11 to 615
(7) Find the average of the first 2704 even numbers.
(8) Find the average of odd numbers from 15 to 1009
(9) Find the average of the first 3310 odd numbers.
(10) Find the average of even numbers from 12 to 208