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MCQs Math


Question:     Find the average of even numbers from 10 to 950


Correct Answer  480

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 950

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 950 are

10, 12, 14, . . . . 950

After observing the above list of the even numbers from 10 to 950 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 950 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 950

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 950

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 950

= 10 + 950/2

= 960/2 = 480

Thus, the average of the even numbers from 10 to 950 = 480 Answer

Method (2) to find the average of the even numbers from 10 to 950

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 950 are

10, 12, 14, . . . . 950

The even numbers from 10 to 950 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 950

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 950

950 = 10 + (n – 1) × 2

⇒ 950 = 10 + 2 n – 2

⇒ 950 = 10 – 2 + 2 n

⇒ 950 = 8 + 2 n

After transposing 8 to LHS

⇒ 950 – 8 = 2 n

⇒ 942 = 2 n

After rearranging the above expression

⇒ 2 n = 942

After transposing 2 to RHS

⇒ n = 942/2

⇒ n = 471

Thus, the number of terms of even numbers from 10 to 950 = 471

This means 950 is the 471th term.

Finding the sum of the given even numbers from 10 to 950

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 950

= 471/2 (10 + 950)

= 471/2 × 960

= 471 × 960/2

= 452160/2 = 226080

Thus, the sum of all terms of the given even numbers from 10 to 950 = 226080

And, the total number of terms = 471

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 950

= 226080/471 = 480

Thus, the average of the given even numbers from 10 to 950 = 480 Answer


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