Question:
Find the average of even numbers from 10 to 986
Correct Answer
498
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 10 to 986
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 10 to 986 are
10, 12, 14, . . . . 986
After observing the above list of the even numbers from 10 to 986 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 986 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 10 to 986
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 986
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 10 to 986
= 10 + 986/2
= 996/2 = 498
Thus, the average of the even numbers from 10 to 986 = 498 Answer
Method (2) to find the average of the even numbers from 10 to 986
Finding the average of given continuous even numbers after finding their sum
The even numbers from 10 to 986 are
10, 12, 14, . . . . 986
The even numbers from 10 to 986 form an Arithmetic Series in which
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 986
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 10 to 986
986 = 10 + (n – 1) × 2
⇒ 986 = 10 + 2 n – 2
⇒ 986 = 10 – 2 + 2 n
⇒ 986 = 8 + 2 n
After transposing 8 to LHS
⇒ 986 – 8 = 2 n
⇒ 978 = 2 n
After rearranging the above expression
⇒ 2 n = 978
After transposing 2 to RHS
⇒ n = 978/2
⇒ n = 489
Thus, the number of terms of even numbers from 10 to 986 = 489
This means 986 is the 489th term.
Finding the sum of the given even numbers from 10 to 986
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 10 to 986
= 489/2 (10 + 986)
= 489/2 × 996
= 489 × 996/2
= 487044/2 = 243522
Thus, the sum of all terms of the given even numbers from 10 to 986 = 243522
And, the total number of terms = 489
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 10 to 986
= 243522/489 = 498
Thus, the average of the given even numbers from 10 to 986 = 498 Answer
Similar Questions
(1) What is the average of the first 184 even numbers?
(2) Find the average of the first 1517 odd numbers.
(3) Find the average of odd numbers from 13 to 223
(4) Find the average of odd numbers from 15 to 785
(5) Find the average of the first 4366 even numbers.
(6) Find the average of the first 3439 odd numbers.
(7) What is the average of the first 1216 even numbers?
(8) Find the average of odd numbers from 9 to 859
(9) Find the average of odd numbers from 11 to 759
(10) What will be the average of the first 4566 odd numbers?