Average
MCQs Math


Question:     Find the average of even numbers from 10 to 1452


Correct Answer  731

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 1452

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 1452 are

10, 12, 14, . . . . 1452

After observing the above list of the even numbers from 10 to 1452 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 1452 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 1452

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 1452

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 1452

= 10 + 1452/2

= 1462/2 = 731

Thus, the average of the even numbers from 10 to 1452 = 731 Answer

Method (2) to find the average of the even numbers from 10 to 1452

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 1452 are

10, 12, 14, . . . . 1452

The even numbers from 10 to 1452 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 1452

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 1452

1452 = 10 + (n – 1) × 2

⇒ 1452 = 10 + 2 n – 2

⇒ 1452 = 10 – 2 + 2 n

⇒ 1452 = 8 + 2 n

After transposing 8 to LHS

⇒ 1452 – 8 = 2 n

⇒ 1444 = 2 n

After rearranging the above expression

⇒ 2 n = 1444

After transposing 2 to RHS

⇒ n = 1444/2

⇒ n = 722

Thus, the number of terms of even numbers from 10 to 1452 = 722

This means 1452 is the 722th term.

Finding the sum of the given even numbers from 10 to 1452

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 1452

= 722/2 (10 + 1452)

= 722/2 × 1462

= 722 × 1462/2

= 1055564/2 = 527782

Thus, the sum of all terms of the given even numbers from 10 to 1452 = 527782

And, the total number of terms = 722

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 1452

= 527782/722 = 731

Thus, the average of the given even numbers from 10 to 1452 = 731 Answer


Similar Questions

(1) What will be the average of the first 4878 odd numbers?

(2) Find the average of even numbers from 10 to 464

(3) Find the average of the first 2126 even numbers.

(4) Find the average of even numbers from 10 to 1530

(5) Find the average of the first 2813 even numbers.

(6) What will be the average of the first 4905 odd numbers?

(7) What will be the average of the first 4337 odd numbers?

(8) Find the average of the first 2620 even numbers.

(9) Find the average of even numbers from 10 to 1350

(10) Find the average of even numbers from 8 to 1332


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©