Question:
Find the average of even numbers from 10 to 1490
Correct Answer
750
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 10 to 1490
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 10 to 1490 are
10, 12, 14, . . . . 1490
After observing the above list of the even numbers from 10 to 1490 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 1490 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 10 to 1490
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 1490
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 10 to 1490
= 10 + 1490/2
= 1500/2 = 750
Thus, the average of the even numbers from 10 to 1490 = 750 Answer
Method (2) to find the average of the even numbers from 10 to 1490
Finding the average of given continuous even numbers after finding their sum
The even numbers from 10 to 1490 are
10, 12, 14, . . . . 1490
The even numbers from 10 to 1490 form an Arithmetic Series in which
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 1490
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 10 to 1490
1490 = 10 + (n – 1) × 2
⇒ 1490 = 10 + 2 n – 2
⇒ 1490 = 10 – 2 + 2 n
⇒ 1490 = 8 + 2 n
After transposing 8 to LHS
⇒ 1490 – 8 = 2 n
⇒ 1482 = 2 n
After rearranging the above expression
⇒ 2 n = 1482
After transposing 2 to RHS
⇒ n = 1482/2
⇒ n = 741
Thus, the number of terms of even numbers from 10 to 1490 = 741
This means 1490 is the 741th term.
Finding the sum of the given even numbers from 10 to 1490
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 10 to 1490
= 741/2 (10 + 1490)
= 741/2 × 1500
= 741 × 1500/2
= 1111500/2 = 555750
Thus, the sum of all terms of the given even numbers from 10 to 1490 = 555750
And, the total number of terms = 741
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 10 to 1490
= 555750/741 = 750
Thus, the average of the given even numbers from 10 to 1490 = 750 Answer
Similar Questions
(1) Find the average of the first 4297 even numbers.
(2) Find the average of the first 250 odd numbers.
(3) What is the average of the first 1834 even numbers?
(4) What will be the average of the first 4617 odd numbers?
(5) Find the average of even numbers from 8 to 896
(6) Find the average of the first 912 odd numbers.
(7) What is the average of the first 1098 even numbers?
(8) Find the average of the first 4432 even numbers.
(9) Find the average of the first 3648 odd numbers.
(10) Find the average of the first 3558 odd numbers.