Average
MCQs Math


Question:     Find the average of even numbers from 10 to 1578


Correct Answer  794

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 10 to 1578

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 10 to 1578 are

10, 12, 14, . . . . 1578

After observing the above list of the even numbers from 10 to 1578 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 1578 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 10 to 1578

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 1578

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 10 to 1578

= 10 + 1578/2

= 1588/2 = 794

Thus, the average of the even numbers from 10 to 1578 = 794 Answer

Method (2) to find the average of the even numbers from 10 to 1578

Finding the average of given continuous even numbers after finding their sum

The even numbers from 10 to 1578 are

10, 12, 14, . . . . 1578

The even numbers from 10 to 1578 form an Arithmetic Series in which

The First Term (a) = 10

The Common Difference (d) = 2

And the last term (ℓ) = 1578

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 10 to 1578

1578 = 10 + (n – 1) × 2

⇒ 1578 = 10 + 2 n – 2

⇒ 1578 = 10 – 2 + 2 n

⇒ 1578 = 8 + 2 n

After transposing 8 to LHS

⇒ 1578 – 8 = 2 n

⇒ 1570 = 2 n

After rearranging the above expression

⇒ 2 n = 1570

After transposing 2 to RHS

⇒ n = 1570/2

⇒ n = 785

Thus, the number of terms of even numbers from 10 to 1578 = 785

This means 1578 is the 785th term.

Finding the sum of the given even numbers from 10 to 1578

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 10 to 1578

= 785/2 (10 + 1578)

= 785/2 × 1588

= 785 × 1588/2

= 1246580/2 = 623290

Thus, the sum of all terms of the given even numbers from 10 to 1578 = 623290

And, the total number of terms = 785

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 10 to 1578

= 623290/785 = 794

Thus, the average of the given even numbers from 10 to 1578 = 794 Answer


Similar Questions

(1) Find the average of odd numbers from 15 to 217

(2) Find the average of the first 242 odd numbers.

(3) Find the average of the first 3297 even numbers.

(4) What is the average of the first 109 odd numbers?

(5) What will be the average of the first 4624 odd numbers?

(6) Find the average of the first 4631 even numbers.

(7) What is the average of the first 829 even numbers?

(8) Find the average of the first 3757 even numbers.

(9) Find the average of odd numbers from 3 to 415

(10) Find the average of odd numbers from 13 to 1225


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©