Question:
Find the average of even numbers from 10 to 1940
Correct Answer
975
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 10 to 1940
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 10 to 1940 are
10, 12, 14, . . . . 1940
After observing the above list of the even numbers from 10 to 1940 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 1940 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 10 to 1940
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 1940
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 10 to 1940
= 10 + 1940/2
= 1950/2 = 975
Thus, the average of the even numbers from 10 to 1940 = 975 Answer
Method (2) to find the average of the even numbers from 10 to 1940
Finding the average of given continuous even numbers after finding their sum
The even numbers from 10 to 1940 are
10, 12, 14, . . . . 1940
The even numbers from 10 to 1940 form an Arithmetic Series in which
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 1940
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 10 to 1940
1940 = 10 + (n – 1) × 2
⇒ 1940 = 10 + 2 n – 2
⇒ 1940 = 10 – 2 + 2 n
⇒ 1940 = 8 + 2 n
After transposing 8 to LHS
⇒ 1940 – 8 = 2 n
⇒ 1932 = 2 n
After rearranging the above expression
⇒ 2 n = 1932
After transposing 2 to RHS
⇒ n = 1932/2
⇒ n = 966
Thus, the number of terms of even numbers from 10 to 1940 = 966
This means 1940 is the 966th term.
Finding the sum of the given even numbers from 10 to 1940
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 10 to 1940
= 966/2 (10 + 1940)
= 966/2 × 1950
= 966 × 1950/2
= 1883700/2 = 941850
Thus, the sum of all terms of the given even numbers from 10 to 1940 = 941850
And, the total number of terms = 966
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 10 to 1940
= 941850/966 = 975
Thus, the average of the given even numbers from 10 to 1940 = 975 Answer
Similar Questions
(1) Find the average of the first 3091 odd numbers.
(2) Find the average of the first 2842 even numbers.
(3) Find the average of even numbers from 4 to 594
(4) Find the average of the first 3464 odd numbers.
(5) Find the average of the first 3129 odd numbers.
(6) What is the average of the first 627 even numbers?
(7) Find the average of the first 3567 even numbers.
(8) Find the average of the first 2611 even numbers.
(9) Find the average of the first 4137 even numbers.
(10) Find the average of even numbers from 8 to 384