Question:
Find the average of even numbers from 10 to 1976
Correct Answer
993
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 10 to 1976
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 10 to 1976 are
10, 12, 14, . . . . 1976
After observing the above list of the even numbers from 10 to 1976 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 10 to 1976 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 10 to 1976
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 1976
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 10 to 1976
= 10 + 1976/2
= 1986/2 = 993
Thus, the average of the even numbers from 10 to 1976 = 993 Answer
Method (2) to find the average of the even numbers from 10 to 1976
Finding the average of given continuous even numbers after finding their sum
The even numbers from 10 to 1976 are
10, 12, 14, . . . . 1976
The even numbers from 10 to 1976 form an Arithmetic Series in which
The First Term (a) = 10
The Common Difference (d) = 2
And the last term (ℓ) = 1976
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 10 to 1976
1976 = 10 + (n – 1) × 2
⇒ 1976 = 10 + 2 n – 2
⇒ 1976 = 10 – 2 + 2 n
⇒ 1976 = 8 + 2 n
After transposing 8 to LHS
⇒ 1976 – 8 = 2 n
⇒ 1968 = 2 n
After rearranging the above expression
⇒ 2 n = 1968
After transposing 2 to RHS
⇒ n = 1968/2
⇒ n = 984
Thus, the number of terms of even numbers from 10 to 1976 = 984
This means 1976 is the 984th term.
Finding the sum of the given even numbers from 10 to 1976
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 10 to 1976
= 984/2 (10 + 1976)
= 984/2 × 1986
= 984 × 1986/2
= 1954224/2 = 977112
Thus, the sum of all terms of the given even numbers from 10 to 1976 = 977112
And, the total number of terms = 984
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 10 to 1976
= 977112/984 = 993
Thus, the average of the given even numbers from 10 to 1976 = 993 Answer
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