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MCQs Math


Question:     Find the average of even numbers from 12 to 126


Correct Answer  69

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 12 to 126

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 12 to 126 are

12, 14, 16, . . . . 126

After observing the above list of the even numbers from 12 to 126 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 12 to 126 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 12 to 126

The First Term (a) = 12

The Common Difference (d) = 2

And the last term (ℓ) = 126

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 12 to 126

= 12 + 126/2

= 138/2 = 69

Thus, the average of the even numbers from 12 to 126 = 69 Answer

Method (2) to find the average of the even numbers from 12 to 126

Finding the average of given continuous even numbers after finding their sum

The even numbers from 12 to 126 are

12, 14, 16, . . . . 126

The even numbers from 12 to 126 form an Arithmetic Series in which

The First Term (a) = 12

The Common Difference (d) = 2

And the last term (ℓ) = 126

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 12 to 126

126 = 12 + (n – 1) × 2

⇒ 126 = 12 + 2 n – 2

⇒ 126 = 12 – 2 + 2 n

⇒ 126 = 10 + 2 n

After transposing 10 to LHS

⇒ 126 – 10 = 2 n

⇒ 116 = 2 n

After rearranging the above expression

⇒ 2 n = 116

After transposing 2 to RHS

⇒ n = 116/2

⇒ n = 58

Thus, the number of terms of even numbers from 12 to 126 = 58

This means 126 is the 58th term.

Finding the sum of the given even numbers from 12 to 126

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 12 to 126

= 58/2 (12 + 126)

= 58/2 × 138

= 58 × 138/2

= 8004/2 = 4002

Thus, the sum of all terms of the given even numbers from 12 to 126 = 4002

And, the total number of terms = 58

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 12 to 126

= 4002/58 = 69

Thus, the average of the given even numbers from 12 to 126 = 69 Answer


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