Average
MCQs Math


Question:     Find the average of even numbers from 12 to 268


Correct Answer  140

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 12 to 268

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 12 to 268 are

12, 14, 16, . . . . 268

After observing the above list of the even numbers from 12 to 268 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 12 to 268 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 12 to 268

The First Term (a) = 12

The Common Difference (d) = 2

And the last term (ℓ) = 268

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 12 to 268

= 12 + 268/2

= 280/2 = 140

Thus, the average of the even numbers from 12 to 268 = 140 Answer

Method (2) to find the average of the even numbers from 12 to 268

Finding the average of given continuous even numbers after finding their sum

The even numbers from 12 to 268 are

12, 14, 16, . . . . 268

The even numbers from 12 to 268 form an Arithmetic Series in which

The First Term (a) = 12

The Common Difference (d) = 2

And the last term (ℓ) = 268

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 12 to 268

268 = 12 + (n – 1) × 2

⇒ 268 = 12 + 2 n – 2

⇒ 268 = 12 – 2 + 2 n

⇒ 268 = 10 + 2 n

After transposing 10 to LHS

⇒ 268 – 10 = 2 n

⇒ 258 = 2 n

After rearranging the above expression

⇒ 2 n = 258

After transposing 2 to RHS

⇒ n = 258/2

⇒ n = 129

Thus, the number of terms of even numbers from 12 to 268 = 129

This means 268 is the 129th term.

Finding the sum of the given even numbers from 12 to 268

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 12 to 268

= 129/2 (12 + 268)

= 129/2 × 280

= 129 × 280/2

= 36120/2 = 18060

Thus, the sum of all terms of the given even numbers from 12 to 268 = 18060

And, the total number of terms = 129

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 12 to 268

= 18060/129 = 140

Thus, the average of the given even numbers from 12 to 268 = 140 Answer


Similar Questions

(1) Find the average of even numbers from 10 to 900

(2) Find the average of even numbers from 4 to 1698

(3) Find the average of odd numbers from 7 to 661

(4) Find the average of the first 531 odd numbers.

(5) Find the average of the first 3554 even numbers.

(6) Find the average of the first 3768 odd numbers.

(7) Find the average of the first 3086 odd numbers.

(8) Find the average of even numbers from 10 to 1856

(9) Find the average of the first 4582 even numbers.

(10) Find the average of the first 934 odd numbers.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©