Question:
Find the average of even numbers from 12 to 1046
Correct Answer
529
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 12 to 1046
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 12 to 1046 are
12, 14, 16, . . . . 1046
After observing the above list of the even numbers from 12 to 1046 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 12 to 1046 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 12 to 1046
The First Term (a) = 12
The Common Difference (d) = 2
And the last term (ℓ) = 1046
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 12 to 1046
= 12 + 1046/2
= 1058/2 = 529
Thus, the average of the even numbers from 12 to 1046 = 529 Answer
Method (2) to find the average of the even numbers from 12 to 1046
Finding the average of given continuous even numbers after finding their sum
The even numbers from 12 to 1046 are
12, 14, 16, . . . . 1046
The even numbers from 12 to 1046 form an Arithmetic Series in which
The First Term (a) = 12
The Common Difference (d) = 2
And the last term (ℓ) = 1046
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 12 to 1046
1046 = 12 + (n – 1) × 2
⇒ 1046 = 12 + 2 n – 2
⇒ 1046 = 12 – 2 + 2 n
⇒ 1046 = 10 + 2 n
After transposing 10 to LHS
⇒ 1046 – 10 = 2 n
⇒ 1036 = 2 n
After rearranging the above expression
⇒ 2 n = 1036
After transposing 2 to RHS
⇒ n = 1036/2
⇒ n = 518
Thus, the number of terms of even numbers from 12 to 1046 = 518
This means 1046 is the 518th term.
Finding the sum of the given even numbers from 12 to 1046
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 12 to 1046
= 518/2 (12 + 1046)
= 518/2 × 1058
= 518 × 1058/2
= 548044/2 = 274022
Thus, the sum of all terms of the given even numbers from 12 to 1046 = 274022
And, the total number of terms = 518
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 12 to 1046
= 274022/518 = 529
Thus, the average of the given even numbers from 12 to 1046 = 529 Answer
Similar Questions
(1) Find the average of the first 207 odd numbers.
(2) Find the average of the first 2362 even numbers.
(3) Find the average of the first 3040 even numbers.
(4) Find the average of the first 4046 even numbers.
(5) Find the average of even numbers from 4 to 882
(6) What will be the average of the first 4622 odd numbers?
(7) Find the average of the first 1949 odd numbers.
(8) Find the average of odd numbers from 15 to 1525
(9) Find the average of odd numbers from 9 to 415
(10) Find the average of odd numbers from 3 to 615