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Question:     Find the average of even numbers from 12 to 1066


Correct Answer  539

Solution And Explanation

Solution

Method (1) to find the average of the even numbers from 12 to 1066

Shortcut Trick to find the average of the given continuous even numbers

The even numbers from 12 to 1066 are

12, 14, 16, . . . . 1066

After observing the above list of the even numbers from 12 to 1066 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 12 to 1066 form an Arithmetic Series.

In the Arithmetic Series of the even numbers from 12 to 1066

The First Term (a) = 12

The Common Difference (d) = 2

And the last term (ℓ) = 1066

The average of the numbers forming an Arithmetic Series

= The first term (a) + The last term (ℓ)/2

⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2

Thus, the average of the even numbers from 12 to 1066

= 12 + 1066/2

= 1078/2 = 539

Thus, the average of the even numbers from 12 to 1066 = 539 Answer

Method (2) to find the average of the even numbers from 12 to 1066

Finding the average of given continuous even numbers after finding their sum

The even numbers from 12 to 1066 are

12, 14, 16, . . . . 1066

The even numbers from 12 to 1066 form an Arithmetic Series in which

The First Term (a) = 12

The Common Difference (d) = 2

And the last term (ℓ) = 1066

The Average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers

Finding the number of terms

For an Arithmetic Series, the nth term

an = a + (n – 1) d

Where

a = First term

d = Common difference

n = number of terms

an = nth term

Thus, for the given series of the even numbers from 12 to 1066

1066 = 12 + (n – 1) × 2

⇒ 1066 = 12 + 2 n – 2

⇒ 1066 = 12 – 2 + 2 n

⇒ 1066 = 10 + 2 n

After transposing 10 to LHS

⇒ 1066 – 10 = 2 n

⇒ 1056 = 2 n

After rearranging the above expression

⇒ 2 n = 1056

After transposing 2 to RHS

⇒ n = 1056/2

⇒ n = 528

Thus, the number of terms of even numbers from 12 to 1066 = 528

This means 1066 is the 528th term.

Finding the sum of the given even numbers from 12 to 1066

The sum of all terms (S) in an Arithmetic Series

= n/2 (a + ℓ)

Where, n = number of terms

a = First term

And, ℓ = Last term

Thus, the sum of all terms (S) of the given even numbers from 12 to 1066

= 528/2 (12 + 1066)

= 528/2 × 1078

= 528 × 1078/2

= 569184/2 = 284592

Thus, the sum of all terms of the given even numbers from 12 to 1066 = 284592

And, the total number of terms = 528

Since, the average of the given numbers

= Sum of the given numbers/Total number of given numbers

Thus, the average of the given even numbers from 12 to 1066

= 284592/528 = 539

Thus, the average of the given even numbers from 12 to 1066 = 539 Answer


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