Question:
Find the average of even numbers from 12 to 1148
Correct Answer
580
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 12 to 1148
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 12 to 1148 are
12, 14, 16, . . . . 1148
After observing the above list of the even numbers from 12 to 1148 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 12 to 1148 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 12 to 1148
The First Term (a) = 12
The Common Difference (d) = 2
And the last term (ℓ) = 1148
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 12 to 1148
= 12 + 1148/2
= 1160/2 = 580
Thus, the average of the even numbers from 12 to 1148 = 580 Answer
Method (2) to find the average of the even numbers from 12 to 1148
Finding the average of given continuous even numbers after finding their sum
The even numbers from 12 to 1148 are
12, 14, 16, . . . . 1148
The even numbers from 12 to 1148 form an Arithmetic Series in which
The First Term (a) = 12
The Common Difference (d) = 2
And the last term (ℓ) = 1148
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 12 to 1148
1148 = 12 + (n – 1) × 2
⇒ 1148 = 12 + 2 n – 2
⇒ 1148 = 12 – 2 + 2 n
⇒ 1148 = 10 + 2 n
After transposing 10 to LHS
⇒ 1148 – 10 = 2 n
⇒ 1138 = 2 n
After rearranging the above expression
⇒ 2 n = 1138
After transposing 2 to RHS
⇒ n = 1138/2
⇒ n = 569
Thus, the number of terms of even numbers from 12 to 1148 = 569
This means 1148 is the 569th term.
Finding the sum of the given even numbers from 12 to 1148
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 12 to 1148
= 569/2 (12 + 1148)
= 569/2 × 1160
= 569 × 1160/2
= 660040/2 = 330020
Thus, the sum of all terms of the given even numbers from 12 to 1148 = 330020
And, the total number of terms = 569
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 12 to 1148
= 330020/569 = 580
Thus, the average of the given even numbers from 12 to 1148 = 580 Answer
Similar Questions
(1) Find the average of odd numbers from 7 to 201
(2) Find the average of even numbers from 10 to 1754
(3) Find the average of the first 2577 even numbers.
(4) Find the average of even numbers from 4 to 1692
(5) Find the average of the first 4763 even numbers.
(6) Find the average of even numbers from 10 to 1934
(7) Find the average of the first 4487 even numbers.
(8) Find the average of even numbers from 12 to 132
(9) Find the average of even numbers from 10 to 1212
(10) Find the average of even numbers from 10 to 1894