Question:
Find the average of even numbers from 12 to 1858
Correct Answer
935
Solution And Explanation
Solution
Method (1) to find the average of the even numbers from 12 to 1858
Shortcut Trick to find the average of the given continuous even numbers
The even numbers from 12 to 1858 are
12, 14, 16, . . . . 1858
After observing the above list of the even numbers from 12 to 1858 we find that the difference between two consecutive terms are equal. This means the list of the even numbers from 12 to 1858 form an Arithmetic Series.
In the Arithmetic Series of the even numbers from 12 to 1858
The First Term (a) = 12
The Common Difference (d) = 2
And the last term (ℓ) = 1858
The average of the numbers forming an Arithmetic Series
= The first term (a) + The last term (ℓ)/2
⇒ The average of numbers forming an Arithmetic Series = a + ℓ/2
Thus, the average of the even numbers from 12 to 1858
= 12 + 1858/2
= 1870/2 = 935
Thus, the average of the even numbers from 12 to 1858 = 935 Answer
Method (2) to find the average of the even numbers from 12 to 1858
Finding the average of given continuous even numbers after finding their sum
The even numbers from 12 to 1858 are
12, 14, 16, . . . . 1858
The even numbers from 12 to 1858 form an Arithmetic Series in which
The First Term (a) = 12
The Common Difference (d) = 2
And the last term (ℓ) = 1858
The Average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, to find the average of the given numbers, first, we need to find their sum and the total number of given numbers
Finding the number of terms
For an Arithmetic Series, the nth term
an = a + (n – 1) d
Where
a = First term
d = Common difference
n = number of terms
an = nth term
Thus, for the given series of the even numbers from 12 to 1858
1858 = 12 + (n – 1) × 2
⇒ 1858 = 12 + 2 n – 2
⇒ 1858 = 12 – 2 + 2 n
⇒ 1858 = 10 + 2 n
After transposing 10 to LHS
⇒ 1858 – 10 = 2 n
⇒ 1848 = 2 n
After rearranging the above expression
⇒ 2 n = 1848
After transposing 2 to RHS
⇒ n = 1848/2
⇒ n = 924
Thus, the number of terms of even numbers from 12 to 1858 = 924
This means 1858 is the 924th term.
Finding the sum of the given even numbers from 12 to 1858
The sum of all terms (S) in an Arithmetic Series
= n/2 (a + ℓ)
Where, n = number of terms
a = First term
And, ℓ = Last term
Thus, the sum of all terms (S) of the given even numbers from 12 to 1858
= 924/2 (12 + 1858)
= 924/2 × 1870
= 924 × 1870/2
= 1727880/2 = 863940
Thus, the sum of all terms of the given even numbers from 12 to 1858 = 863940
And, the total number of terms = 924
Since, the average of the given numbers
= Sum of the given numbers/Total number of given numbers
Thus, the average of the given even numbers from 12 to 1858
= 863940/924 = 935
Thus, the average of the given even numbers from 12 to 1858 = 935 Answer
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