Simple Interest
MCQs Math


Question:     Michael had to pay $3498 in order to furnish the loan taken 3 years before. If the rate of simple interest was 2% then find the sum borrowed.


Correct Answer  $3300

Solution And Explanation

Solution

Given,

Amount (A) = $3498

Rate of Simple Interest (R) = 2%

Time (T) = 3 years

Thus, Principal (P) = ?

Method (1) Using Formula

Calculation of the Principal using forumula when Amount, Time and Rate of Simple Interest are given

Formula to find the Principal (P)

Amount (A) = Principal (P) + Principal (P) × Rate (R) × Time (T)

⇒ Amount (A) = Principal (P) [1 + Rate (R) × Time (T)]

⇒ A = P (1 + RT)

Using the formula to find the Amount (A), the fourth can be calculated if any three of A, P, R, and T are given

In the given question, we need to find the Principal (P)

Therefore, by substituting, Amount, Rate, and Time, in the formula A = P (1 + RT) we get

$3498 = P (1 + 2% × 3)

⇒ $3498 = P (1 + 2/100 × 3)

⇒ $3498 = P (1 + 2 × 3/100)

⇒ $3498 = P (1 + 6/100)

⇒ $3498 = P (100 + 6/100)

⇒ $3498 = P × 106/100

⇒ P × 106/100 = $3498

⇒ P = 3498/106/100

⇒ P = 3498 × 100/106

⇒ P = 3498 × 100/106

⇒ P = 349800/106

⇒ P = $3300

Thus, the sum borrowed (P) = $3300 Answer

Method (1) Using Unitary Method

Calculation of the Principal using unitary method when Amount, Time and Rate of Simple Interest are given

Calculation of the Simple Interest

Let, the principal = 100

Here, since rate of simple interest = 2% per annum

Thus, Interest = 2% of principal

⇒ Interest = 2% of 100 = 2

Thus, Simple Interest for 1 year = 2

Calculation of the Amount

Since, in the question, time = 3 years

So, we need to calculate the simple interest for the given time period, which is 3 years

Thus, Simple Interest for 3 years = 3 × Simple Interest for 1 year

= 3 × 2 = 6

Thus, simple interest for 3 years = 6

Thus, Amount (A) = Principal + Interest

⇒ Amount = 100 + 6 = 106

Calculation of the Principal

Now,

∵ If the Amount is 106, then the Principal = 100

∴ If the Amount is 1, then the Principal = 100/106

∴ If the Amount is 3498, then the Principal = 100/106 × 3498

= 100 × 3498/106

= 349800/106

= 3300

Thus, Principal = $3300

Thus, the sum borrowed = $3300 Answer


Similar Questions

(1) In how much time a principal of $3200 will amount to $3520 at a simple interest of 5% per annum?

(2) What amount will be due after 2 years if Charles borrowed a sum of $3450 at a 10% simple interest?

(3) Find the amount to be paid if Jessica borrowed a sum of $5750 at 6% simple interest for 8 years.

(4) If Mark paid $5104 to settle his loan which he had taken 4 years before at a simple interest of 4%, then find the loan taken.

(5) Find the amount to be paid if Linda borrowed a sum of $5350 at 2% simple interest for 7 years.

(6) Barbara took a loan of $5100 at the rate of 7% simple interest per annum. If he paid an amount of $8670 to clear the loan, then find the time period of the loan.

(7) Calculate the amount due if Thomas borrowed a sum of $3800 at 5% simple interest for 3 years.

(8) Christopher took a loan of $6000 at the rate of 6% simple interest per annum. If he paid an amount of $9600 to clear the loan, then find the time period of the loan.

(9) Find the amount to be paid if Robert borrowed a sum of $5100 at 2% simple interest for 7 years.

(10) Joshua had to pay $5635 in order to furnish the loan taken 3 years before. If the rate of simple interest was 5% then find the sum borrowed.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©