Simple Interest
MCQs Math


Question:     Michael had to pay $3597 in order to furnish the loan taken 3 years before. If the rate of simple interest was 3% then find the sum borrowed.


Correct Answer  $3300

Solution And Explanation

Solution

Given,

Amount (A) = $3597

Rate of Simple Interest (R) = 3%

Time (T) = 3 years

Thus, Principal (P) = ?

Method (1) Using Formula

Calculation of the Principal using forumula when Amount, Time and Rate of Simple Interest are given

Formula to find the Principal (P)

Amount (A) = Principal (P) + Principal (P) × Rate (R) × Time (T)

⇒ Amount (A) = Principal (P) [1 + Rate (R) × Time (T)]

⇒ A = P (1 + RT)

Using the formula to find the Amount (A), the fourth can be calculated if any three of A, P, R, and T are given

In the given question, we need to find the Principal (P)

Therefore, by substituting, Amount, Rate, and Time, in the formula A = P (1 + RT) we get

$3597 = P (1 + 3% × 3)

⇒ $3597 = P (1 + 3/100 × 3)

⇒ $3597 = P (1 + 3 × 3/100)

⇒ $3597 = P (1 + 9/100)

⇒ $3597 = P (100 + 9/100)

⇒ $3597 = P × 109/100

⇒ P × 109/100 = $3597

⇒ P = 3597/109/100

⇒ P = 3597 × 100/109

⇒ P = 3597 × 100/109

⇒ P = 359700/109

⇒ P = $3300

Thus, the sum borrowed (P) = $3300 Answer

Method (1) Using Unitary Method

Calculation of the Principal using unitary method when Amount, Time and Rate of Simple Interest are given

Calculation of the Simple Interest

Let, the principal = 100

Here, since rate of simple interest = 3% per annum

Thus, Interest = 3% of principal

⇒ Interest = 3% of 100 = 3

Thus, Simple Interest for 1 year = 3

Calculation of the Amount

Since, in the question, time = 3 years

So, we need to calculate the simple interest for the given time period, which is 3 years

Thus, Simple Interest for 3 years = 3 × Simple Interest for 1 year

= 3 × 3 = 9

Thus, simple interest for 3 years = 9

Thus, Amount (A) = Principal + Interest

⇒ Amount = 100 + 9 = 109

Calculation of the Principal

Now,

∵ If the Amount is 109, then the Principal = 100

∴ If the Amount is 1, then the Principal = 100/109

∴ If the Amount is 3597, then the Principal = 100/109 × 3597

= 100 × 3597/109

= 359700/109

= 3300

Thus, Principal = $3300

Thus, the sum borrowed = $3300 Answer


Similar Questions

(1) Nancy took a loan of $6300 at the rate of 6% simple interest per annum. If he paid an amount of $8568 to clear the loan, then find the time period of the loan.

(2) What amount does John have to pay after 5 years if he takes a loan of $3200 at 3% simple interest?

(3) Calculate the amount due if David borrowed a sum of $3400 at 3% simple interest for 4 years.

(4) What amount does Thomas have to pay after 6 years if he takes a loan of $3800 at 2% simple interest?

(5) Find the amount to be paid if Charles borrowed a sum of $5900 at 2% simple interest for 8 years.

(6) Calculate the amount due after 9 years if Sarah borrowed a sum of $5850 at a rate of 6% simple interest.

(7) What amount does Barbara have to pay after 5 years if he takes a loan of $3550 at 4% simple interest?

(8) David took a loan of $4800 at the rate of 6% simple interest per annum. If he paid an amount of $7392 to clear the loan, then find the time period of the loan.

(9) What amount does Richard have to pay after 6 years if he takes a loan of $3600 at 8% simple interest?

(10) Patricia took a loan of $4300 at the rate of 9% simple interest per annum. If he paid an amount of $7009 to clear the loan, then find the time period of the loan.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©