Simple Interest
MCQs Math


Question:     David had to pay $3808 in order to furnish the loan taken 3 years before. If the rate of simple interest was 4% then find the sum borrowed.


Correct Answer  $3400

Solution And Explanation

Solution

Given,

Amount (A) = $3808

Rate of Simple Interest (R) = 4%

Time (T) = 3 years

Thus, Principal (P) = ?

Method (1) Using Formula

Calculation of the Principal using forumula when Amount, Time and Rate of Simple Interest are given

Formula to find the Principal (P)

Amount (A) = Principal (P) + Principal (P) × Rate (R) × Time (T)

⇒ Amount (A) = Principal (P) [1 + Rate (R) × Time (T)]

⇒ A = P (1 + RT)

Using the formula to find the Amount (A), the fourth can be calculated if any three of A, P, R, and T are given

In the given question, we need to find the Principal (P)

Therefore, by substituting, Amount, Rate, and Time, in the formula A = P (1 + RT) we get

$3808 = P (1 + 4% × 3)

⇒ $3808 = P (1 + 4/100 × 3)

⇒ $3808 = P (1 + 4 × 3/100)

⇒ $3808 = P (1 + 12/100)

⇒ $3808 = P (100 + 12/100)

⇒ $3808 = P × 112/100

⇒ P × 112/100 = $3808

⇒ P = 3808/112/100

⇒ P = 3808 × 100/112

⇒ P = 3808 × 100/112

⇒ P = 380800/112

⇒ P = $3400

Thus, the sum borrowed (P) = $3400 Answer

Method (1) Using Unitary Method

Calculation of the Principal using unitary method when Amount, Time and Rate of Simple Interest are given

Calculation of the Simple Interest

Let, the principal = 100

Here, since rate of simple interest = 4% per annum

Thus, Interest = 4% of principal

⇒ Interest = 4% of 100 = 4

Thus, Simple Interest for 1 year = 4

Calculation of the Amount

Since, in the question, time = 3 years

So, we need to calculate the simple interest for the given time period, which is 3 years

Thus, Simple Interest for 3 years = 3 × Simple Interest for 1 year

= 3 × 4 = 12

Thus, simple interest for 3 years = 12

Thus, Amount (A) = Principal + Interest

⇒ Amount = 100 + 12 = 112

Calculation of the Principal

Now,

∵ If the Amount is 112, then the Principal = 100

∴ If the Amount is 1, then the Principal = 100/112

∴ If the Amount is 3808, then the Principal = 100/112 × 3808

= 100 × 3808/112

= 380800/112

= 3400

Thus, Principal = $3400

Thus, the sum borrowed = $3400 Answer


Similar Questions

(1) In how much time a principal of $3000 will amount to $3270 at a simple interest of 3% per annum?

(2) Calculate the amount due if John borrowed a sum of $3200 at 6% simple interest for 3 years.

(3) Anthony took a loan of $6600 at the rate of 6% simple interest per annum. If he paid an amount of $10560 to clear the loan, then find the time period of the loan.

(4) Find the amount to be paid if Joseph borrowed a sum of $5700 at 6% simple interest for 8 years.

(5) Find the amount to be paid if Karen borrowed a sum of $5950 at 5% simple interest for 8 years.

(6) Robert took a loan of $4200 at the rate of 6% simple interest per annum. If he paid an amount of $6468 to clear the loan, then find the time period of the loan.

(7) Michael had to pay $3498 in order to furnish the loan taken 3 years before. If the rate of simple interest was 2% then find the sum borrowed.

(8) Betty had to pay $4760 in order to furnish the loan taken 3 years before. If the rate of simple interest was 4% then find the sum borrowed.

(9) Find the amount to be paid if Patricia borrowed a sum of $5150 at 8% simple interest for 7 years.

(10) Michael took a loan of $4600 at the rate of 9% simple interest per annum. If he paid an amount of $8326 to clear the loan, then find the time period of the loan.


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