Simple Interest
MCQs Math


Question:     If Linda paid $3618 to settle his loan which he had taken 4 years before at a simple interest of 2%, then find the loan taken.


Correct Answer  $3350

Solution And Explanation

Solution

Given,

Amount (A) = $3618

Rate of Simple Interest (R) = 2%

Time (T) = 4 years

Thus, Principal (P) = ?

Method (1) Using Formula

Calculation of the Principal using forumula when Amount, Time and Rate of Simple Interest are given

Formula to find the Principal (P)

Amount (A) = Principal (P) + Principal (P) × Rate (R) × Time (T)

⇒ Amount (A) = Principal (P) [1 + Rate (R) × Time (T)]

⇒ A = P (1 + RT)

Using the formula to find the Amount (A), the fourth can be calculated if any three of A, P, R, and T are given

In the given question, we need to find the Principal (P)

Therefore, by substituting, Amount, Rate, and Time, in the formula A = P (1 + RT) we get

$3618 = P (1 + 2% × 4)

⇒ $3618 = P (1 + 2/100 × 4)

⇒ $3618 = P (1 + 2 × 4/100)

⇒ $3618 = P (1 + 8/100)

⇒ $3618 = P (100 + 8/100)

⇒ $3618 = P × 108/100

⇒ P × 108/100 = $3618

⇒ P = 3618/108/100

⇒ P = 3618 × 100/108

⇒ P = 3618 × 100/108

⇒ P = 361800/108

⇒ P = $3350

Thus, the sum borrowed (P) = $3350 Answer

Method (1) Using Unitary Method

Calculation of the Principal using unitary method when Amount, Time and Rate of Simple Interest are given

Calculation of the Simple Interest

Let, the principal = 100

Here, since rate of simple interest = 2% per annum

Thus, Interest = 2% of principal

⇒ Interest = 2% of 100 = 2

Thus, Simple Interest for 1 year = 2

Calculation of the Amount

Since, in the question, time = 4 years

So, we need to calculate the simple interest for the given time period, which is 4 years

Thus, Simple Interest for 4 years = 4 × Simple Interest for 1 year

= 4 × 2 = 8

Thus, simple interest for 4 years = 8

Thus, Amount (A) = Principal + Interest

⇒ Amount = 100 + 8 = 108

Calculation of the Principal

Now,

∵ If the Amount is 108, then the Principal = 100

∴ If the Amount is 1, then the Principal = 100/108

∴ If the Amount is 3618, then the Principal = 100/108 × 3618

= 100 × 3618/108

= 361800/108

= 3350

Thus, Principal = $3350

Thus, the sum borrowed = $3350 Answer


Similar Questions

(1) Calculate the amount due if John borrowed a sum of $3200 at 8% simple interest for 3 years.

(2) Calculate the amount due after 9 years if Thomas borrowed a sum of $5800 at a rate of 8% simple interest.

(3) Steven had to pay $5152 in order to furnish the loan taken 3 years before. If the rate of simple interest was 4% then find the sum borrowed.

(4) Richard took a loan of $5200 at the rate of 8% simple interest per annum. If he paid an amount of $8112 to clear the loan, then find the time period of the loan.

(5) What amount does Mary have to pay after 5 years if he takes a loan of $3050 at 7% simple interest?

(6) What amount does William have to pay after 6 years if he takes a loan of $3500 at 4% simple interest?

(7) What amount will be due after 2 years if Andrew borrowed a sum of $3900 at a 9% simple interest?

(8) Find the amount to be paid if Susan borrowed a sum of $5650 at 4% simple interest for 8 years.

(9) Nancy took a loan of $6300 at the rate of 8% simple interest per annum. If he paid an amount of $9828 to clear the loan, then find the time period of the loan.

(10) Nancy took a loan of $6300 at the rate of 9% simple interest per annum. If he paid an amount of $9702 to clear the loan, then find the time period of the loan.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©