Simple Interest
MCQs Math


Question:     In how much time a principal of $3050 will amount to $3294 at a simple interest of 4% per annum?


Correct Answer  2

Solution And Explanation

Solution

Given,

Principal (P) = $3050

Rate of Simple Interest (R) = 4% per annum

Amount (A) = $3294

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $3294 – $3050 = $244

Thus, Simple Interest = $244

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 244/3050 × 4

= 24400/12200

= 2 years (using formula)

Thus, Time (T) = 2 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $3050

Rate of Simple Interest (R) = 4% per annum

Simple Interest = $244 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 4% of Principal

= 4% of $3050

= 4/100 × 3050

= 4 × 3050/100

= 12200/100 = 122

Thus, simple Interest for 1 year = $122

Now,

∵ If the simple Interest is $122, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/122 years

∴ If the simple Interest is $244, then the time = 1/122 × 244 years

= 1 × 244/122 years

= 244/122 = 2 years

Thus, time (T) = 2 years Answer


Similar Questions

(1) What amount does Robert have to pay after 6 years if he takes a loan of $3100 at 9% simple interest?

(2) What amount will be due after 2 years if Paul borrowed a sum of $3850 at a 6% simple interest?

(3) Calculate the amount due after 10 years if Robert borrowed a sum of $5100 at a rate of 2% simple interest.

(4) What amount does Jessica have to pay after 6 years if he takes a loan of $3750 at 6% simple interest?

(5) Richard had to pay $4140 in order to furnish the loan taken 3 years before. If the rate of simple interest was 5% then find the sum borrowed.

(6) What amount does Susan have to pay after 6 years if he takes a loan of $3650 at 10% simple interest?

(7) What amount does Christopher have to pay after 6 years if he takes a loan of $4000 at 8% simple interest?

(8) Lisa took a loan of $6100 at the rate of 8% simple interest per annum. If he paid an amount of $9028 to clear the loan, then find the time period of the loan.

(9) What amount does Elizabeth have to pay after 5 years if he takes a loan of $3450 at 4% simple interest?

(10) If John paid $3584 to settle his loan which he had taken 4 years before at a simple interest of 3%, then find the loan taken.


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