Simple Interest
MCQs Math


Question:   ( 1 of 10 )  In how much time a principal of $3200 will amount to $3584 at a simple interest of 3% per annum?

(A)  4 47/50 Or, 247/50
(B)  8 47/50 Or, 447/50
(C)  4 141/50 Or, 341/50
(D)  4 94/50 Or, 294/50

You selected   6

Correct Answer  4

Solution And Explanation

Solution

Given,

Principal (P) = $3200

Rate of Simple Interest (R) = 3% per annum

Amount (A) = $3584

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $3584 – $3200 = $384

Thus, Simple Interest = $384

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 384/3200 × 3

= 38400/9600

= 4 years (using formula)

Thus, Time (T) = 4 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $3200

Rate of Simple Interest (R) = 3% per annum

Simple Interest = $384 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 3% of Principal

= 3% of $3200

= 3/100 × 3200

= 3 × 3200/100

= 9600/100 = 96

Thus, simple Interest for 1 year = $96

Now,

∵ If the simple Interest is $96, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/96 years

∴ If the simple Interest is $384, then the time = 1/96 × 384 years

= 1 × 384/96 years

= 384/96 = 4 years

Thus, time (T) = 4 years Answer


Similar Questions

(1) If William paid $4200 to settle his loan which he had taken 4 years before at a simple interest of 5%, then find the loan taken.

(2) Find the amount to be paid if Richard borrowed a sum of $5600 at 7% simple interest for 8 years.

(3) Michael had to pay $3498 in order to furnish the loan taken 3 years before. If the rate of simple interest was 2% then find the sum borrowed.

(4) Calculate the amount due after 10 years if Barbara borrowed a sum of $5550 at a rate of 6% simple interest.

(5) Find the amount to be paid if James borrowed a sum of $5000 at 8% simple interest for 7 years.

(6) Find the amount to be paid if Sarah borrowed a sum of $5850 at 2% simple interest for 7 years.

(7) What amount does David have to pay after 6 years if he takes a loan of $3400 at 9% simple interest?

(8) What amount does Charles have to pay after 5 years if he takes a loan of $3900 at 8% simple interest?

(9) Calculate the amount due if Susan borrowed a sum of $3650 at 8% simple interest for 4 years.

(10) John took a loan of $4400 at the rate of 10% simple interest per annum. If he paid an amount of $7040 to clear the loan, then find the time period of the loan.


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