Simple Interest
MCQs Math


Question:   ( 1 of 10 )  John took a loan of $4400 at the rate of 8% simple interest per annum. If he paid an amount of $6512 to clear the loan, then find the time period of the loan.

(A)  59
(B)  30.5
(C)  61
(D)  60

You selected   9

Correct Answer  6

Solution And Explanation

Solution

Given,

Principal (P) = $4400

Rate of Simple Interest (R) = 8% per annum

Amount (A) = $6512

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $6512 – $4400 = $2112

Thus, Simple Interest = $2112

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 2112/4400 × 8

= 211200/35200

= 6 years (using formula)

Thus, Time (T) = 6 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $4400

Rate of Simple Interest (R) = 8% per annum

Simple Interest = $2112 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 8% of Principal

= 8% of $4400

= 8/100 × 4400

= 8 × 4400/100

= 35200/100 = 352

Thus, simple Interest for 1 year = $352

Now,

∵ If the simple Interest is $352, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/352 years

∴ If the simple Interest is $2112, then the time = 1/352 × 2112 years

= 1 × 2112/352 years

= 2112/352 = 6 years

Thus, time (T) = 6 years Answer


Similar Questions

(1) If Jennifer paid $3510 to settle his loan which he had taken 4 years before at a simple interest of 2%, then find the loan taken.

(2) Calculate the amount due if Jessica borrowed a sum of $3750 at 6% simple interest for 3 years.

(3) Christopher took a loan of $6000 at the rate of 6% simple interest per annum. If he paid an amount of $8160 to clear the loan, then find the time period of the loan.

(4) John had to pay $3680 in order to furnish the loan taken 3 years before. If the rate of simple interest was 5% then find the sum borrowed.

(5) Richard took a loan of $5200 at the rate of 6% simple interest per annum. If he paid an amount of $7384 to clear the loan, then find the time period of the loan.

(6) In how much time a principal of $3150 will amount to $3622.5 at a simple interest of 5% per annum?

(7) What amount does Patricia have to pay after 5 years if he takes a loan of $3150 at 7% simple interest?

(8) Find the amount to be paid if Michael borrowed a sum of $5300 at 10% simple interest for 7 years.

(9) How much loan did Betty borrow 5 years ago at a rate of simple interest 5% per annum, if he paid $7812.5 to clear it?

(10) Calculate the amount due after 10 years if Thomas borrowed a sum of $5800 at a rate of 2% simple interest.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©