Simple Interest
MCQs Math


Question:     David took a loan of $4800 at the rate of 8% simple interest per annum. If he paid an amount of $7104 to clear the loan, then find the time period of the loan.


Correct Answer  6

Solution And Explanation

Solution

Given,

Principal (P) = $4800

Rate of Simple Interest (R) = 8% per annum

Amount (A) = $7104

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $7104 – $4800 = $2304

Thus, Simple Interest = $2304

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 2304/4800 × 8

= 230400/38400

= 6 years (using formula)

Thus, Time (T) = 6 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $4800

Rate of Simple Interest (R) = 8% per annum

Simple Interest = $2304 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 8% of Principal

= 8% of $4800

= 8/100 × 4800

= 8 × 4800/100

= 38400/100 = 384

Thus, simple Interest for 1 year = $384

Now,

∵ If the simple Interest is $384, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/384 years

∴ If the simple Interest is $2304, then the time = 1/384 × 2304 years

= 1 × 2304/384 years

= 2304/384 = 6 years

Thus, time (T) = 6 years Answer


Similar Questions

(1) What amount does Sarah have to pay after 6 years if he takes a loan of $3850 at 8% simple interest?

(2) Find the amount to be paid if Barbara borrowed a sum of $5550 at 9% simple interest for 7 years.

(3) What amount does Elizabeth have to pay after 6 years if he takes a loan of $3450 at 2% simple interest?

(4) Andrew had to pay $5376 in order to furnish the loan taken 3 years before. If the rate of simple interest was 4% then find the sum borrowed.

(5) Calculate the amount due if Mary borrowed a sum of $3050 at 10% simple interest for 4 years.

(6) What amount will be due after 2 years if David borrowed a sum of $3200 at a 10% simple interest?

(7) Calculate the amount due after 9 years if Sarah borrowed a sum of $5850 at a rate of 3% simple interest.

(8) In how much time a principal of $3100 will amount to $3720 at a simple interest of 5% per annum?

(9) What amount will be due after 2 years if John borrowed a sum of $3100 at a 8% simple interest?

(10) Calculate the amount due after 9 years if Robert borrowed a sum of $5100 at a rate of 5% simple interest.


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