Simple Interest
MCQs Math


Question:     Donald took a loan of $7000 at the rate of 9% simple interest per annum. If he paid an amount of $10780 to clear the loan, then find the time period of the loan.


Correct Answer  6

Solution And Explanation

Solution

Given,

Principal (P) = $7000

Rate of Simple Interest (R) = 9% per annum

Amount (A) = $10780

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $10780 – $7000 = $3780

Thus, Simple Interest = $3780

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 3780/7000 × 9

= 378000/63000

= 6 years (using formula)

Thus, Time (T) = 6 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $7000

Rate of Simple Interest (R) = 9% per annum

Simple Interest = $3780 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 9% of Principal

= 9% of $7000

= 9/100 × 7000

= 9 × 7000/100

= 63000/100 = 630

Thus, simple Interest for 1 year = $630

Now,

∵ If the simple Interest is $630, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/630 years

∴ If the simple Interest is $3780, then the time = 1/630 × 3780 years

= 1 × 3780/630 years

= 3780/630 = 6 years

Thus, time (T) = 6 years Answer


Similar Questions

(1) Calculate the amount due if Charles borrowed a sum of $3900 at 6% simple interest for 3 years.

(2) Calculate the amount due if Elizabeth borrowed a sum of $3450 at 5% simple interest for 3 years.

(3) If Mark paid $5280 to settle his loan which he had taken 4 years before at a simple interest of 5%, then find the loan taken.

(4) If Michael paid $3960 to settle his loan which he had taken 4 years before at a simple interest of 5%, then find the loan taken.

(5) Christopher had to pay $4480 in order to furnish the loan taken 3 years before. If the rate of simple interest was 4% then find the sum borrowed.

(6) Calculate the amount due if Linda borrowed a sum of $3350 at 6% simple interest for 3 years.

(7) What amount does Mary have to pay after 5 years if he takes a loan of $3050 at 10% simple interest?

(8) What amount does James have to pay after 5 years if he takes a loan of $3000 at 6% simple interest?

(9) Find the amount to be paid if Charles borrowed a sum of $5900 at 6% simple interest for 7 years.

(10) Andrew had to pay $5376 in order to furnish the loan taken 3 years before. If the rate of simple interest was 4% then find the sum borrowed.


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