Simple Interest
MCQs Math


Question:   ( 1 of 10 )  Sandra took a loan of $6900 at the rate of 7% simple interest per annum. If he paid an amount of $10281 to clear the loan, then find the time period of the loan.

(A)  59
(B)  30.5
(C)  61
(D)  60

You selected   10.5

Correct Answer  7

Solution And Explanation

Solution

Given,

Principal (P) = $6900

Rate of Simple Interest (R) = 7% per annum

Amount (A) = $10281

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $10281 – $6900 = $3381

Thus, Simple Interest = $3381

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 3381/6900 × 7

= 338100/48300

= 7 years (using formula)

Thus, Time (T) = 7 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $6900

Rate of Simple Interest (R) = 7% per annum

Simple Interest = $3381 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 7% of Principal

= 7% of $6900

= 7/100 × 6900

= 7 × 6900/100

= 48300/100 = 483

Thus, simple Interest for 1 year = $483

Now,

∵ If the simple Interest is $483, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/483 years

∴ If the simple Interest is $3381, then the time = 1/483 × 3381 years

= 1 × 3381/483 years

= 3381/483 = 7 years

Thus, time (T) = 7 years Answer


Similar Questions

(1) What amount will be due after 2 years if Kenneth borrowed a sum of $4000 at a 8% simple interest?

(2) What amount does Christopher have to pay after 6 years if he takes a loan of $4000 at 2% simple interest?

(3) Calculate the amount due if Christopher borrowed a sum of $4000 at 4% simple interest for 3 years.

(4) David had to pay $3910 in order to furnish the loan taken 3 years before. If the rate of simple interest was 5% then find the sum borrowed.

(5) Find the amount to be paid if Christopher borrowed a sum of $6000 at 7% simple interest for 8 years.

(6) Find the amount to be paid if Jessica borrowed a sum of $5750 at 6% simple interest for 7 years.

(7) Find the amount to be paid if Sarah borrowed a sum of $5850 at 6% simple interest for 7 years.

(8) If David paid $3944 to settle his loan which he had taken 4 years before at a simple interest of 4%, then find the loan taken.

(9) Barbara took a loan of $5100 at the rate of 9% simple interest per annum. If he paid an amount of $7854 to clear the loan, then find the time period of the loan.

(10) Richard took a loan of $5200 at the rate of 10% simple interest per annum. If he paid an amount of $9360 to clear the loan, then find the time period of the loan.


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