Simple Interest
MCQs Math


Question:     Linda took a loan of $4700 at the rate of 9% simple interest per annum. If he paid an amount of $8084 to clear the loan, then find the time period of the loan.


Correct Answer  8

Solution And Explanation

Solution

Given,

Principal (P) = $4700

Rate of Simple Interest (R) = 9% per annum

Amount (A) = $8084

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $8084 – $4700 = $3384

Thus, Simple Interest = $3384

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 3384/4700 × 9

= 338400/42300

= 8 years (using formula)

Thus, Time (T) = 8 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $4700

Rate of Simple Interest (R) = 9% per annum

Simple Interest = $3384 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 9% of Principal

= 9% of $4700

= 9/100 × 4700

= 9 × 4700/100

= 42300/100 = 423

Thus, simple Interest for 1 year = $423

Now,

∵ If the simple Interest is $423, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/423 years

∴ If the simple Interest is $3384, then the time = 1/423 × 3384 years

= 1 × 3384/423 years

= 3384/423 = 8 years

Thus, time (T) = 8 years Answer


Similar Questions

(1) What amount does Susan have to pay after 6 years if he takes a loan of $3650 at 2% simple interest?

(2) What amount does Linda have to pay after 5 years if he takes a loan of $3350 at 10% simple interest?

(3) If Michelle paid $5742 to settle his loan which he had taken 4 years before at a simple interest of 4%, then find the loan taken.

(4) Thomas took a loan of $5600 at the rate of 10% simple interest per annum. If he paid an amount of $8960 to clear the loan, then find the time period of the loan.

(5) What amount will be due after 2 years if Joshua borrowed a sum of $3950 at a 6% simple interest?

(6) Find the amount to be paid if Jennifer borrowed a sum of $5250 at 10% simple interest for 8 years.

(7) Anthony took a loan of $6600 at the rate of 8% simple interest per annum. If he paid an amount of $9768 to clear the loan, then find the time period of the loan.

(8) What amount does Richard have to pay after 6 years if he takes a loan of $3600 at 4% simple interest?

(9) Calculate the amount due if Linda borrowed a sum of $3350 at 8% simple interest for 4 years.

(10) Christopher took a loan of $6000 at the rate of 7% simple interest per annum. If he paid an amount of $10200 to clear the loan, then find the time period of the loan.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©