Simple Interest
MCQs Math


Question:     Joseph took a loan of $5400 at the rate of 9% simple interest per annum. If he paid an amount of $9288 to clear the loan, then find the time period of the loan.


Correct Answer  8

Solution And Explanation

Solution

Given,

Principal (P) = $5400

Rate of Simple Interest (R) = 9% per annum

Amount (A) = $9288

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $9288 – $5400 = $3888

Thus, Simple Interest = $3888

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 3888/5400 × 9

= 388800/48600

= 8 years (using formula)

Thus, Time (T) = 8 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $5400

Rate of Simple Interest (R) = 9% per annum

Simple Interest = $3888 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 9% of Principal

= 9% of $5400

= 9/100 × 5400

= 9 × 5400/100

= 48600/100 = 486

Thus, simple Interest for 1 year = $486

Now,

∵ If the simple Interest is $486, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/486 years

∴ If the simple Interest is $3888, then the time = 1/486 × 3888 years

= 1 × 3888/486 years

= 3888/486 = 8 years

Thus, time (T) = 8 years Answer


Similar Questions

(1) If Anthony paid $4816 to settle his loan which he had taken 4 years before at a simple interest of 3%, then find the loan taken.

(2) What amount does Mary have to pay after 6 years if he takes a loan of $3050 at 4% simple interest?

(3) What amount will be due after 2 years if Thomas borrowed a sum of $3400 at a 6% simple interest?

(4) What amount does Karen have to pay after 6 years if he takes a loan of $3950 at 3% simple interest?

(5) Calculate the amount due if Mary borrowed a sum of $3050 at 9% simple interest for 4 years.

(6) Mary took a loan of $4100 at the rate of 8% simple interest per annum. If he paid an amount of $7052 to clear the loan, then find the time period of the loan.

(7) What amount does Mary have to pay after 5 years if he takes a loan of $3050 at 8% simple interest?

(8) Calculate the amount due if Linda borrowed a sum of $3350 at 9% simple interest for 4 years.

(9) Calculate the amount due after 9 years if James borrowed a sum of $5000 at a rate of 7% simple interest.

(10) John took a loan of $4400 at the rate of 7% simple interest per annum. If he paid an amount of $6864 to clear the loan, then find the time period of the loan.


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©