Simple Interest
MCQs Math


Question:     Sandra took a loan of $6900 at the rate of 9% simple interest per annum. If he paid an amount of $11868 to clear the loan, then find the time period of the loan.


Correct Answer  8

Solution And Explanation

Solution

Given,

Principal (P) = $6900

Rate of Simple Interest (R) = 9% per annum

Amount (A) = $11868

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $11868 – $6900 = $4968

Thus, Simple Interest = $4968

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 4968/6900 × 9

= 496800/62100

= 8 years (using formula)

Thus, Time (T) = 8 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $6900

Rate of Simple Interest (R) = 9% per annum

Simple Interest = $4968 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 9% of Principal

= 9% of $6900

= 9/100 × 6900

= 9 × 6900/100

= 62100/100 = 621

Thus, simple Interest for 1 year = $621

Now,

∵ If the simple Interest is $621, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/621 years

∴ If the simple Interest is $4968, then the time = 1/621 × 4968 years

= 1 × 4968/621 years

= 4968/621 = 8 years

Thus, time (T) = 8 years Answer


Similar Questions

(1) Lisa took a loan of $6100 at the rate of 9% simple interest per annum. If he paid an amount of $9943 to clear the loan, then find the time period of the loan.

(2) Betty took a loan of $6500 at the rate of 10% simple interest per annum. If he paid an amount of $10400 to clear the loan, then find the time period of the loan.

(3) What amount does John have to pay after 6 years if he takes a loan of $3200 at 3% simple interest?

(4) What amount does Sarah have to pay after 5 years if he takes a loan of $3850 at 6% simple interest?

(5) In how much time a principal of $3100 will amount to $3565 at a simple interest of 3% per annum?

(6) What amount will be due after 2 years if Paul borrowed a sum of $3850 at a 5% simple interest?

(7) Calculate the amount due if Joseph borrowed a sum of $3700 at 5% simple interest for 3 years.

(8) Calculate the amount due if Elizabeth borrowed a sum of $3450 at 9% simple interest for 3 years.

(9) Find the amount to be paid if Richard borrowed a sum of $5600 at 5% simple interest for 7 years.

(10) Steven had to pay $4876 in order to furnish the loan taken 3 years before. If the rate of simple interest was 2% then find the sum borrowed.


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