Simple Interest
MCQs Math


Question:     Linda took a loan of $4700 at the rate of 6% simple interest per annum. If he paid an amount of $7238 to clear the loan, then find the time period of the loan.


Correct Answer  9

Solution And Explanation

Solution

Given,

Principal (P) = $4700

Rate of Simple Interest (R) = 6% per annum

Amount (A) = $7238

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $7238 – $4700 = $2538

Thus, Simple Interest = $2538

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 2538/4700 × 6

= 253800/28200

= 9 years (using formula)

Thus, Time (T) = 9 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $4700

Rate of Simple Interest (R) = 6% per annum

Simple Interest = $2538 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 6% of Principal

= 6% of $4700

= 6/100 × 4700

= 6 × 4700/100

= 28200/100 = 282

Thus, simple Interest for 1 year = $282

Now,

∵ If the simple Interest is $282, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/282 years

∴ If the simple Interest is $2538, then the time = 1/282 × 2538 years

= 1 × 2538/282 years

= 2538/282 = 9 years

Thus, time (T) = 9 years Answer


Similar Questions

(1) Calculate the amount due if Barbara borrowed a sum of $3550 at 6% simple interest for 4 years.

(2) In how much time a principal of $3000 will amount to $3300 at a simple interest of 5% per annum?

(3) What amount does Robert have to pay after 5 years if he takes a loan of $3100 at 4% simple interest?

(4) What amount will be due after 2 years if Mark borrowed a sum of $3700 at a 6% simple interest?

(5) Thomas took a loan of $5600 at the rate of 6% simple interest per annum. If he paid an amount of $8960 to clear the loan, then find the time period of the loan.

(6) Calculate the amount due after 9 years if Linda borrowed a sum of $5350 at a rate of 6% simple interest.

(7) If Betty paid $5100 to settle his loan which he had taken 4 years before at a simple interest of 5%, then find the loan taken.

(8) Find the amount to be paid if Thomas borrowed a sum of $5800 at 6% simple interest for 8 years.

(9) Mary took a loan of $4100 at the rate of 10% simple interest per annum. If he paid an amount of $8200 to clear the loan, then find the time period of the loan.

(10) Find the amount to be paid if Christopher borrowed a sum of $6000 at 9% simple interest for 8 years.


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