Simple Interest
MCQs Math


Question:     Susan took a loan of $5300 at the rate of 7% simple interest per annum. If he paid an amount of $8639 to clear the loan, then find the time period of the loan.


Correct Answer  9

Solution And Explanation

Solution

Given,

Principal (P) = $5300

Rate of Simple Interest (R) = 7% per annum

Amount (A) = $8639

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $8639 – $5300 = $3339

Thus, Simple Interest = $3339

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 3339/5300 × 7

= 333900/37100

= 9 years (using formula)

Thus, Time (T) = 9 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $5300

Rate of Simple Interest (R) = 7% per annum

Simple Interest = $3339 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 7% of Principal

= 7% of $5300

= 7/100 × 5300

= 7 × 5300/100

= 37100/100 = 371

Thus, simple Interest for 1 year = $371

Now,

∵ If the simple Interest is $371, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/371 years

∴ If the simple Interest is $3339, then the time = 1/371 × 3339 years

= 1 × 3339/371 years

= 3339/371 = 9 years

Thus, time (T) = 9 years Answer


Similar Questions

(1) What amount does Linda have to pay after 5 years if he takes a loan of $3350 at 2% simple interest?

(2) In how much time a principal of $3050 will amount to $3233 at a simple interest of 3% per annum?

(3) Barbara took a loan of $5100 at the rate of 9% simple interest per annum. If he paid an amount of $7854 to clear the loan, then find the time period of the loan.

(4) If Linda paid $3618 to settle his loan which he had taken 4 years before at a simple interest of 2%, then find the loan taken.

(5) Find the amount to be paid if Sarah borrowed a sum of $5850 at 9% simple interest for 7 years.

(6) Calculate the amount due if William borrowed a sum of $3500 at 2% simple interest for 3 years.

(7) Calculate the amount due if Christopher borrowed a sum of $4000 at 2% simple interest for 3 years.

(8) Donald had to pay $4770 in order to furnish the loan taken 3 years before. If the rate of simple interest was 2% then find the sum borrowed.

(9) How much loan did Joshua borrow 5 years ago at a rate of simple interest 5% per annum, if he paid $8625 to clear it?

(10) Calculate the amount due if James borrowed a sum of $3000 at 8% simple interest for 4 years.


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