Simple Interest
MCQs Math


Question:     Mark took a loan of $6800 at the rate of 7% simple interest per annum. If he paid an amount of $11084 to clear the loan, then find the time period of the loan.


Correct Answer  9

Solution And Explanation

Solution

Given,

Principal (P) = $6800

Rate of Simple Interest (R) = 7% per annum

Amount (A) = $11084

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $11084 – $6800 = $4284

Thus, Simple Interest = $4284

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 4284/6800 × 7

= 428400/47600

= 9 years (using formula)

Thus, Time (T) = 9 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $6800

Rate of Simple Interest (R) = 7% per annum

Simple Interest = $4284 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 7% of Principal

= 7% of $6800

= 7/100 × 6800

= 7 × 6800/100

= 47600/100 = 476

Thus, simple Interest for 1 year = $476

Now,

∵ If the simple Interest is $476, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/476 years

∴ If the simple Interest is $4284, then the time = 1/476 × 4284 years

= 1 × 4284/476 years

= 4284/476 = 9 years

Thus, time (T) = 9 years Answer


Similar Questions

(1) Find the amount to be paid if David borrowed a sum of $5400 at 9% simple interest for 7 years.

(2) Calculate the amount due if James borrowed a sum of $3000 at 7% simple interest for 3 years.

(3) Find the amount to be paid if Sarah borrowed a sum of $5850 at 4% simple interest for 7 years.

(4) If David paid $3808 to settle his loan which he had taken 4 years before at a simple interest of 3%, then find the loan taken.

(5) In how much time a principal of $3150 will amount to $3402 at a simple interest of 4% per annum?

(6) What amount does Mary have to pay after 5 years if he takes a loan of $3050 at 5% simple interest?

(7) Calculate the amount due after 9 years if Karen borrowed a sum of $5950 at a rate of 9% simple interest.

(8) How much loan did Jacob borrow 5 years ago at a rate of simple interest 4% per annum, if he paid $9600 to clear it?

(9) What amount does Richard have to pay after 6 years if he takes a loan of $3600 at 9% simple interest?

(10) What amount does Charles have to pay after 6 years if he takes a loan of $3900 at 8% simple interest?


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