Simple Interest
MCQs Math


Question:     Barbara took a loan of $5100 at the rate of 9% simple interest per annum. If he paid an amount of $9231 to clear the loan, then find the time period of the loan.


Correct Answer  9

Solution And Explanation

Solution

Given,

Principal (P) = $5100

Rate of Simple Interest (R) = 9% per annum

Amount (A) = $9231

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $9231 – $5100 = $4131

Thus, Simple Interest = $4131

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 4131/5100 × 9

= 413100/45900

= 9 years (using formula)

Thus, Time (T) = 9 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $5100

Rate of Simple Interest (R) = 9% per annum

Simple Interest = $4131 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 9% of Principal

= 9% of $5100

= 9/100 × 5100

= 9 × 5100/100

= 45900/100 = 459

Thus, simple Interest for 1 year = $459

Now,

∵ If the simple Interest is $459, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/459 years

∴ If the simple Interest is $4131, then the time = 1/459 × 4131 years

= 1 × 4131/459 years

= 4131/459 = 9 years

Thus, time (T) = 9 years Answer


Similar Questions

(1) What amount will be due after 2 years if James borrowed a sum of $3000 at a 10% simple interest?

(2) How much loan did Sandra borrow 5 years ago at a rate of simple interest 3% per annum, if he paid $7417.5 to clear it?

(3) John took a loan of $4400 at the rate of 10% simple interest per annum. If he paid an amount of $7040 to clear the loan, then find the time period of the loan.

(4) How much loan did Lisa borrow 5 years ago at a rate of simple interest 4% per annum, if he paid $7260 to clear it?

(5) What amount does Karen have to pay after 5 years if he takes a loan of $3950 at 5% simple interest?

(6) How much loan did Kenneth borrow 5 years ago at a rate of simple interest 5% per annum, if he paid $8750 to clear it?

(7) Calculate the amount due after 9 years if John borrowed a sum of $5200 at a rate of 4% simple interest.

(8) What amount does Karen have to pay after 5 years if he takes a loan of $3950 at 7% simple interest?

(9) Find the amount to be paid if Charles borrowed a sum of $5900 at 3% simple interest for 7 years.

(10) What amount does Michael have to pay after 6 years if he takes a loan of $3300 at 10% simple interest?


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©