Simple Interest
MCQs Math


Question:     Daniel took a loan of $6200 at the rate of 9% simple interest per annum. If he paid an amount of $11780 to clear the loan, then find the time period of the loan.


Correct Answer  10

Solution And Explanation

Solution

Given,

Principal (P) = $6200

Rate of Simple Interest (R) = 9% per annum

Amount (A) = $11780

Thus, time (T) = ?

Method (1) Using Formula

Calculation of Simple Interest, when Principal and Amount are given

Formual to Calculate Simple Interest when Principal and Amount are given

We know that, Amount (A) = Principal (P) + Simple Interest (SI)

⇒ Simple Interest (SI) = Amount – Principal

⇒ SI = $11780 – $6200 = $5580

Thus, Simple Interest = $5580

Calculation of the Time using forumula when Amount, Simple Interest and Principal are known

Formula to find the Time (T)

Time (T) = 100 × Simple Interest/Principal × Rate of Interest

⇒ T = 100 × SI/P × R

Thus, Time (T) = 100 × 5580/6200 × 9

= 558000/55800

= 10 years (using formula)

Thus, Time (T) = 10 years (from time taken before calculation)Answer

Calculation of the Time using Unitary Method when Amount, Simple Interest and Principal are known

Here, we have

Principal (P) = $6200

Rate of Simple Interest (R) = 9% per annum

Simple Interest = $5580 (As calculated above by subtracting Principal from the Amount given)

We know that, interest is calculated on the basis of the Principal.

This means Simple Interest for 1 year = Rate of simple interest × Principal

Thus, Simple Interest for 1 year = 9% of Principal

= 9% of $6200

= 9/100 × 6200

= 9 × 6200/100

= 55800/100 = 558

Thus, simple Interest for 1 year = $558

Now,

∵ If the simple Interest is $558, then the time = 1 year

∴ If the simple Interest is $1, then the time = 1/558 years

∴ If the simple Interest is $5580, then the time = 1/558 × 5580 years

= 1 × 5580/558 years

= 5580/558 = 10 years

Thus, time (T) = 10 years Answer


Similar Questions

(1) Calculate the amount due if Robert borrowed a sum of $3100 at 3% simple interest for 4 years.

(2) Find the amount to be paid if Charles borrowed a sum of $5900 at 8% simple interest for 8 years.

(3) What amount will be due after 2 years if John borrowed a sum of $3100 at a 6% simple interest?

(4) Find the amount to be paid if Jennifer borrowed a sum of $5250 at 4% simple interest for 7 years.

(5) What amount does Christopher have to pay after 6 years if he takes a loan of $4000 at 5% simple interest?

(6) What amount does Thomas have to pay after 5 years if he takes a loan of $3800 at 4% simple interest?

(7) Karen had to pay $4424 in order to furnish the loan taken 3 years before. If the rate of simple interest was 4% then find the sum borrowed.

(8) Calculate the amount due after 9 years if Joseph borrowed a sum of $5700 at a rate of 5% simple interest.

(9) Calculate the amount due if Robert borrowed a sum of $3100 at 2% simple interest for 4 years.

(10) Anthony took a loan of $6600 at the rate of 7% simple interest per annum. If he paid an amount of $9372 to clear the loan, then find the time period of the loan.


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