Time and Work
MCQs Math


Question:     If Kenneth can finish the work in 42 days and Gregory can finish the same work in 45 days, then in how many days both can finish the work together?


Correct Answer  21 21/29 days or 21.724 days

Solution And Explanation

Solution

Given,

The number of days to finish the work by Kenneth = 42 days

And, the number of days to finish the same work by Gregory = 45 days

Thus, the number of days to finish the work by Kenneth and Gregory together = ?

Here,

∵ In 42 days the work done by Kenneth = 1

∴ In 1 day, the work done by Kenneth = 1/42 part

Similarly,

∵ In 45 days the work done by Gregory = 1

∴ In 1 day, the work done by Gregory = 1/45 part

Now, in 1 day, the work done by Kenneth and Gregory together

= In 1 day work done by Kenneth + In 1 day the work done by Gregory

= 1/42 + 1/45

= 15 + 14/630

= 29/630 part of work

This means in 1 day, 29/630 part of work is done by Kenneth and Gregory working together.

Now, the number of days required to finish 29/630 part of work by Kenneth + Gregory working together = 1

∴ the number of days required to finish 1 work by Kenneth + Gregory together

= 1/29/630

= 1 × 630/29 = 630/29 days

= 21 21/29 days = or 21.724 days

Thus, Kenneth and Gregory working together will finish the work in 21 21/29 days = or 21.724 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in a days, and B can finish the same work in b days,
then working together the number of days require to finish the work
= a × b/a + b days.

Here given,

The number of days required to finish the work by Kenneth = 42 days

And the number of days required to finish the same work by Gregory = 45 days

Thus, the number of days required to finish the work Kenneth and Gregory working together = ?

Here a = 42 days

And, b = 45 days

Thus, using formula a × b/a + b days

The number of days required to finish the work when Kenneth and Gregory working together

= 42 × 45/42 + 45 days

= 1890/87 days

= 1890 ÷ 3/87 ÷ 3 = 630/29 days

= 21 21/29 days or 21.724

Thus, Kenneth and Gregory together will finish the work in 21 21/29 days or 21.724 days Answer


Similar Questions

(1) If Anthony can finish the work in 31 days and Jeffrey can finish the same work in 36 days, then in how many days both can finish the work together?

(2) Elizabeth can finish a work in 14 days. Susan can finish the same work in 19 days while Jessica can finish the work in 24 days. How long will it take to finish it if they work together?

(3) William can finish a work in 11 days. Richard can finish the same work in 12 days while Joseph can finish the work in 13 days. How long will it take to finish it if they work together?

(4) Anthony can finish a work in 31 days. Donald can finish the same work in 36 days while Steven can finish the work in 41 days. How long will it take to finish it if they work together?

(5) Donald can finish a work in 35 days. Paul can finish the same work in 40 days while Andrew can finish the work in 45 days. How long will it take to finish it if they work together?

(6) Joseph can finish a work in 19 days. Charles can finish the same work in 24 days while Christopher can finish the work in 29 days. How long will it take to finish it if they work together?

(7) If Elizabeth can finish the work in 11 days and Daniel can finish the same work in 14 days, then in how many days both can finish the work together?

(8) Betty can finish a work in 26 days. Margaret can finish the same work in 27 days while Sandra can finish the work in 28 days. How long will it take to finish it if they work together?

(9) Anna can finish a work in 74 days. Pamela can finish the same work in 79 days while Emma can finish the work in 84 days. How long will it take to finish it if they work together?

(10) If Dorothy can finish the work in 47 days and Jack can finish the same work in 51 days, then in how many days both can finish the work together?


NCERT Solution and CBSE Notes for class twelve, eleventh, tenth, ninth, seventh, sixth, fifth, fourth and General Math for competitive Exams. ©