Time and Work
MCQs Math


Question:     If Jack can finish a work in 8 days and Bill can finish the same work in 12 days, then in how many days they both can finish the work working together?


Correct Answer  4 4/5 days or 4.8 days

Solution And Explanation

Solution

Given,

The number of days to finish the work by Jack = 8 days

And, the number of days to finish the same work by Bill = 12 days

Thus, the number of days to finish the work by Jack and Bill working together = ?

Here, ∵ In 8 days the work done by Jack = 1

∴ In 1 day, the work done by Jack = 1/8 part

Similarly, ∵ In 12 days the work done by Bill = 1

∴ In 1 day, the work done by Bill = 1/12 part

Now, in 1 day, the work done by Jack and Bill working together

= In 1 day work done by Jack + In 1 day the work done by Bill

= 1/8 + 1/12

= 3 + 2/24

= 5/24 part of work

This means in 1 day, 5/24 part of work is done by Jack and Bill working together.

Now, the number of days required to finish 5/24 part of work by Jack + Bill working together = 1

∴ the number of days required to finish 1 work by Robert + Bob working together

= 1/5/24

= 1 × 24/5 days = 24/5 days

= 4 4/5 days = 4.8 days

Thus, Jack and Bill working together will finish the work in 4 4/5 days = 4.8 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in "a" days, and B can finish the same work in "b" days,
then working together the number of days require to finish the work
= a × b/a + b days.

Here given,

The number of days to finish the work by Jack = 8 days

And, the number of days to finish the same work by Bill = 12 days

Thus, the number of days to finish the work by Jack and Bill working together = ?

Here "a" = 8 days

And, "b" = 12 days

Thus, using formula a × b/a + b days

The number of days require to finish the work when Jack and Bill working together

= 8 × 12/8 + 12

= 24 × 4/5 × 4 = 24/5 days

= 4 4/5 days or 4.8 days

Thus, Jack and Bill working together will finish the work in 4 4/5 days or 4.8 days Answer


Similar Questions

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