Time and Work
MCQs Math


Question:     Carol can finish a work in 46 days. Dorothy can finish the same work in 51 days while Melissa can finish the work in 56 days. How long will it take to finish it if they work together?


Correct Answer  16 3464/3889 days or 16.891 days

Solution And Explanation

Solution

Given,

The number of days required to finish a piece of work by Carol = 46 days

And, the number of days required to finish the same work by Dorothy = 51 days

And, the number of days required to finish the same work by Melissa = 56 days

Thus, the number of days required to finish the work by all of them if they work together = ?

Here,

∵ In 46 days the work is done by Carol = 1

∴ The work done by Carol in 1 day = 1/46

Similarly,

∵ In 51 days the work is done by Dorothy = 1

∴ The work done by Dorothy in 1 day = 1/51

Similarly,

∵ In 56 days the work is done by Melissa = 1

∴ The work done by Melissa in 1 day = 1/56 part

Now, the work done by Carol, Dorothy, and Melissa together in 1 day

= Carol's 1 day work + Dorothy's 1 day work + Melissa's 1 day work

= 1/46 + 1/51 + 1/56

= 1428 + 1288 + 1173/65688

= 3889/65688 part of work

This means in 1 day, 3889/65688 part of work is done by Carol, Dorothy and Melissa working together.

Now, the number of days required to finish 3889/65688 part of work by Carol, Dorothy, and Melissa working together = 1

∴ the number of days required to finish the whole work (1 work) by Carol + Dorothy + Melissa together

= 1/3889/65688

= 1 × 65688/3889 = 65688/3889 days

= 16 3464/3889 days = or 16.891 days

Thus, Carol, Dorothy, and Melissa working together will finish the total work (1 work) in 16 3464/3889 days = or 16.891 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in a days, B can finish the same work in b days, and C can finish the work in c days
then working together the number of days required to finish the work
= a × b × c/ab + ac + bc days.

Here given,

The number of days required to finish the work by Carol = 46 days

And the number of days required to finish the same work by Dorothy = 51 days

And the number of days required to finish the work by Melissa = 56 days

Thus, the number of days required to finish the work by Carol, Dorothy, and Melissa together = ?

Here a = 46 days

And, b = 51 days

And, c = 56 days

Thus, using formula a × b × c/ab + ac + bc days

The number of days required to finish the work when Carol, Dorothy, and Melissa working together

= 46 × 51 × 56/46 × 51 + 46 × 56 + 51 × 56 days

= 131376/2346 + 2576 + 2856 days

= 131376/7778 days

= 131376/7778 days

= 131376 ÷ 2/7778 ÷ 2 = 65688/3889 days

= 16 3464/3889 days or 16.891

Thus, Carol, Dorothy, and Melissa together will finish the work in 16 3464/3889 days or 16.891 days Answer


Similar Questions

(1) Donald can finish a work in 35 days. Paul can finish the same work in 40 days while Andrew can finish the work in 45 days. How long will it take to finish it if they work together?

(2) If Annie can finish a work in 6 days and Bobby can finish the same work in 12 days, then in how many days they both can finish the work working together?

(3) If Patricia can finish the work in 8 days and William can finish the same work in 13 days, then in how many days both can finish the work together?

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(6) Betty can finish a work in 30 days. Sandra can finish the same work in 35 days while Ashley can finish the work in 40 days. How long will it take to finish it if they work together?

(7) Joseph can finish a work in 15 days. Thomas can finish the same work in 16 days while Charles can finish the work in 17 days. How long will it take to finish it if they work together?

(8) If Kenneth can finish the work in 42 days and Gregory can finish the same work in 46 days, then in how many days both can finish the work together?

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