Time and Work
MCQs Math


Question:     Ronald can finish a work in 55 days. Jason can finish the same work in 60 days while Jeffrey can finish the work in 65 days. How long will it take to finish it if they work together?


Correct Answer  19 391/431 days or 19.907 days

Solution And Explanation

Solution

Given,

The number of days required to finish a piece of work by Ronald = 55 days

And, the number of days required to finish the same work by Jason = 60 days

And, the number of days required to finish the same work by Jeffrey = 65 days

Thus, the number of days required to finish the work by all of them if they work together = ?

Here,

∵ In 55 days the work is done by Ronald = 1

∴ The work done by Ronald in 1 day = 1/55

Similarly,

∵ In 60 days the work is done by Jason = 1

∴ The work done by Jason in 1 day = 1/60

Similarly,

∵ In 65 days the work is done by Jeffrey = 1

∴ The work done by Jeffrey in 1 day = 1/65 part

Now, the work done by Ronald, Jason, and Jeffrey together in 1 day

= Ronald's 1 day work + Jason's 1 day work + Jeffrey's 1 day work

= 1/55 + 1/60 + 1/65

= 156 + 143 + 132/8580

= 431/8580 part of work

This means in 1 day, 431/8580 part of work is done by Ronald, Jason and Jeffrey working together.

Now, the number of days required to finish 431/8580 part of work by Ronald, Jason, and Jeffrey working together = 1

∴ the number of days required to finish the whole work (1 work) by Ronald + Jason + Jeffrey together

= 1/431/8580

= 1 × 8580/431 = 8580/431 days

= 19 391/431 days = or 19.907 days

Thus, Ronald, Jason, and Jeffrey working together will finish the total work (1 work) in 19 391/431 days = or 19.907 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in a days, B can finish the same work in b days, and C can finish the work in c days
then working together the number of days required to finish the work
= a × b × c/ab + ac + bc days.

Here given,

The number of days required to finish the work by Ronald = 55 days

And the number of days required to finish the same work by Jason = 60 days

And the number of days required to finish the work by Jeffrey = 65 days

Thus, the number of days required to finish the work by Ronald, Jason, and Jeffrey together = ?

Here a = 55 days

And, b = 60 days

And, c = 65 days

Thus, using formula a × b × c/ab + ac + bc days

The number of days required to finish the work when Ronald, Jason, and Jeffrey working together

= 55 × 60 × 65/55 × 60 + 55 × 65 + 60 × 65 days

= 214500/3300 + 3575 + 3900 days

= 214500/10775 days

= 214500/10775 days

= 214500 ÷ 25/10775 ÷ 25 = 8580/431 days

= 19 391/431 days or 19.907

Thus, Ronald, Jason, and Jeffrey together will finish the work in 19 391/431 days or 19.907 days Answer


Similar Questions

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(6) If Jessica can finish the work in 20 days and Paul can finish the same work in 25 days, then in how many days both can finish the work together?

(7) If Amanda can finish the work in 45 days and Patrick can finish the same work in 48 days, then in how many days both can finish the work together?

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