Time and Work
MCQs Math


Question:     Eric can finish a work in 71 days. Stephen can finish the same work in 76 days while Larry can finish the work in 81 days. How long will it take to finish it if they work together?


Correct Answer  25 4501/17303 days or 25.26 days

Solution And Explanation

Solution

Given,

The number of days required to finish a piece of work by Eric = 71 days

And, the number of days required to finish the same work by Stephen = 76 days

And, the number of days required to finish the same work by Larry = 81 days

Thus, the number of days required to finish the work by all of them if they work together = ?

Here,

∵ In 71 days the work is done by Eric = 1

∴ The work done by Eric in 1 day = 1/71

Similarly,

∵ In 76 days the work is done by Stephen = 1

∴ The work done by Stephen in 1 day = 1/76

Similarly,

∵ In 81 days the work is done by Larry = 1

∴ The work done by Larry in 1 day = 1/81 part

Now, the work done by Eric, Stephen, and Larry together in 1 day

= Eric's 1 day work + Stephen's 1 day work + Larry's 1 day work

= 1/71 + 1/76 + 1/81

= 6156 + 5751 + 5396/437076

= 17303/437076 part of work

This means in 1 day, 17303/437076 part of work is done by Eric, Stephen and Larry working together.

Now, the number of days required to finish 17303/437076 part of work by Eric, Stephen, and Larry working together = 1

∴ the number of days required to finish the whole work (1 work) by Eric + Stephen + Larry together

= 1/17303/437076

= 1 × 437076/17303 = 437076/17303 days

= 25 4501/17303 days = or 25.26 days

Thus, Eric, Stephen, and Larry working together will finish the total work (1 work) in 25 4501/17303 days = or 25.26 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in a days, B can finish the same work in b days, and C can finish the work in c days
then working together the number of days required to finish the work
= a × b × c/ab + ac + bc days.

Here given,

The number of days required to finish the work by Eric = 71 days

And the number of days required to finish the same work by Stephen = 76 days

And the number of days required to finish the work by Larry = 81 days

Thus, the number of days required to finish the work by Eric, Stephen, and Larry together = ?

Here a = 71 days

And, b = 76 days

And, c = 81 days

Thus, using formula a × b × c/ab + ac + bc days

The number of days required to finish the work when Eric, Stephen, and Larry working together

= 71 × 76 × 81/71 × 76 + 71 × 81 + 76 × 81 days

= 437076/5396 + 5751 + 6156 days

= 437076/17303 days

= 437076/17303 days

= 25 4501/17303 days or 25.26

Thus, Eric, Stephen, and Larry together will finish the work in 25 4501/17303 days or 25.26 days Answer


Similar Questions

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(2) If Debra can finish the work in 92 days and Elijah can finish the same work in 97 days, then in how many days both can finish the work together?

(3) If David can finish the work in 32 days and Christopher can finish the same work in 48 days, then in how many days both can finish the work together?

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(6) Deborah can finish a work in 50 days. Stephanie can finish the same work in 51 days while Rebecca can finish the work in 52 days. How long will it take to finish it if they work together?

(7) Thomas can finish a work in 17 days. Charles can finish the same work in 18 days while Christopher can finish the work in 19 days. How long will it take to finish it if they work together?

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