Time and Work
MCQs Math


Question:     Catherine can finish a work in 100 days. Heather can finish the same work in 105 days while Diane can finish the work in 110 days. How long will it take to finish it if they work together?


Correct Answer  34 626/661 days or 34.947 days

Solution And Explanation

Solution

Given,

The number of days required to finish a piece of work by Catherine = 100 days

And, the number of days required to finish the same work by Heather = 105 days

And, the number of days required to finish the same work by Diane = 110 days

Thus, the number of days required to finish the work by all of them if they work together = ?

Here,

∵ In 100 days the work is done by Catherine = 1

∴ The work done by Catherine in 1 day = 1/100

Similarly,

∵ In 105 days the work is done by Heather = 1

∴ The work done by Heather in 1 day = 1/105

Similarly,

∵ In 110 days the work is done by Diane = 1

∴ The work done by Diane in 1 day = 1/110 part

Now, the work done by Catherine, Heather, and Diane together in 1 day

= Catherine's 1 day work + Heather's 1 day work + Diane's 1 day work

= 1/100 + 1/105 + 1/110

= 231 + 220 + 210/23100

= 661/23100 part of work

This means in 1 day, 661/23100 part of work is done by Catherine, Heather and Diane working together.

Now, the number of days required to finish 661/23100 part of work by Catherine, Heather, and Diane working together = 1

∴ the number of days required to finish the whole work (1 work) by Catherine + Heather + Diane together

= 1/661/23100

= 1 × 23100/661 = 23100/661 days

= 34 626/661 days = or 34.947 days

Thus, Catherine, Heather, and Diane working together will finish the total work (1 work) in 34 626/661 days = or 34.947 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in a days, B can finish the same work in b days, and C can finish the work in c days
then working together the number of days required to finish the work
= a × b × c/ab + ac + bc days.

Here given,

The number of days required to finish the work by Catherine = 100 days

And the number of days required to finish the same work by Heather = 105 days

And the number of days required to finish the work by Diane = 110 days

Thus, the number of days required to finish the work by Catherine, Heather, and Diane together = ?

Here a = 100 days

And, b = 105 days

And, c = 110 days

Thus, using formula a × b × c/ab + ac + bc days

The number of days required to finish the work when Catherine, Heather, and Diane working together

= 100 × 105 × 110/100 × 105 + 100 × 110 + 105 × 110 days

= 1155000/10500 + 11000 + 11550 days

= 1155000/33050 days

= 1155000/33050 days

= 1155000 ÷ 50/33050 ÷ 50 = 23100/661 days

= 34 626/661 days or 34.947

Thus, Catherine, Heather, and Diane together will finish the work in 34 626/661 days or 34.947 days Answer


Similar Questions

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(2) Amanda can finish a work in 44 days. Dorothy can finish the same work in 45 days while Melissa can finish the work in 46 days. How long will it take to finish it if they work together?

(3) Kenneth can finish a work in 41 days. Kevin can finish the same work in 42 days while Brian can finish the work in 43 days. How long will it take to finish it if they work together?

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(5) If William can finish the work in 12 days and Matthew can finish the same work in 16 days, then in how many days both can finish the work together?

(6) If Rebecca can finish the work in 58 days and Henry can finish the same work in 63 days, then in how many days both can finish the work together?

(7) Daniel can finish a work in 23 days. Matthew can finish the same work in 24 days while Anthony can finish the work in 25 days. How long will it take to finish it if they work together?

(8) If Jennifer can finish the work in 29 days and Joseph can finish the same work in 45 days, then in how many days both can finish the work together?

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