Time and Work
MCQs Math


Question:     Richard can finish a work in 13 days. Joseph can finish the same work in 14 days while Thomas can finish the work in 15 days. How long will it take to finish it if they work together?


Correct Answer  4 382/587 days or 4.651 days

Solution And Explanation

Solution

Given,

The number of days required to finish a piece of work by Richard = 13 days

And, the number of days required to finish the same work by Joseph = 14 days

And, the number of days required to finish the same work by Thomas = 15 days

Thus, the number of days required to finish the work by all of them if they work together = ?

Here,

∵ In 13 days the work is done by Richard = 1

∴ The work done by Richard in 1 day = 1/13

Similarly,

∵ In 14 days the work is done by Joseph = 1

∴ The work done by Joseph in 1 day = 1/14

Similarly,

∵ In 15 days the work is done by Thomas = 1

∴ The work done by Thomas in 1 day = 1/15 part

Now, the work done by Richard, Joseph, and Thomas together in 1 day

= Richard's 1 day work + Joseph's 1 day work + Thomas's 1 day work

= 1/13 + 1/14 + 1/15

= 210 + 195 + 182/2730

= 587/2730 part of work

This means in 1 day, 587/2730 part of work is done by Richard, Joseph and Thomas working together.

Now, the number of days required to finish 587/2730 part of work by Richard, Joseph, and Thomas working together = 1

∴ the number of days required to finish the whole work (1 work) by Richard + Joseph + Thomas together

= 1/587/2730

= 1 × 2730/587 = 2730/587 days

= 4 382/587 days = or 4.651 days

Thus, Richard, Joseph, and Thomas working together will finish the total work (1 work) in 4 382/587 days = or 4.651 days Answer

Shortcut Trick to solve the problems based on time and work using formula

Case: If A can finish a work in a days, B can finish the same work in b days, and C can finish the work in c days
then working together the number of days required to finish the work
= a × b × c/ab + ac + bc days.

Here given,

The number of days required to finish the work by Richard = 13 days

And the number of days required to finish the same work by Joseph = 14 days

And the number of days required to finish the work by Thomas = 15 days

Thus, the number of days required to finish the work by Richard, Joseph, and Thomas together = ?

Here a = 13 days

And, b = 14 days

And, c = 15 days

Thus, using formula a × b × c/ab + ac + bc days

The number of days required to finish the work when Richard, Joseph, and Thomas working together

= 13 × 14 × 15/13 × 14 + 13 × 15 + 14 × 15 days

= 2730/182 + 195 + 210 days

= 2730/587 days

= 2730/587 days

= 4 382/587 days or 4.651

Thus, Richard, Joseph, and Thomas together will finish the work in 4 382/587 days or 4.651 days Answer


Similar Questions

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(2) If Mark can finish the work in 30 days and Jacob can finish the same work in 33 days, then in how many days both can finish the work together?

(3) If Edward can finish the work in 57 days and Nathan can finish the same work in 62 days, then in how many days both can finish the work together?

(4) If Linda can finish the work in 12 days and Charles can finish the same work in 17 days, then in how many days both can finish the work together?

(5) Thomas can finish a work in 17 days. Charles can finish the same work in 18 days while Christopher can finish the work in 19 days. How long will it take to finish it if they work together?

(6) If Robert can finish a work in 5 days and Bob can finish the same work in 6 days, then in how many days they both can finish the work working together?

(7) Karen can finish a work in 24 days. Nancy can finish the same work in 29 days while Betty can finish the work in 34 days. How long will it take to finish it if they work together?

(8) Paul can finish a work in 35 days. Andrew can finish the same work in 36 days while Joshua can finish the work in 37 days. How long will it take to finish it if they work together?

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